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3 years ago

8

Answer the statistical measures and create a box and whiskers plot for the following set of data. You may optionally click and d

rag the numbers into numerical order.
4
,
5
,
5
,
7
,
9
,
10
,
10
,
10
,
11
,
12
,
13
,
15
4,5,5,7,9,10,10,10,11,12,13,15
Min: Q1: Med: Q3: Max:
Create the box plot by dragging the lines:
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
x

1 answer:

ratelena [41]3 years ago

3 0

sorry

look im trying to finish a challange u need premium if your going toask that big of a quietion my dude/dudet

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How would you verify tan3x = (3tanx - tan^3 x) / ( 1 - 3tan^2 x) and sin4x = (cosx)(4sinx - 8sin^3x) step-by-step?

padilas [110]

Hope this helps you.

5 0

3 years ago

Part A). Emily participates in a trivia quiz show. In each round, 20 points are awarded for a correct answer and 10 points are d

rosijanka [135]

Answer

A. -30 points

B. 60 points

Step-by-step explanation:

20 points for correct answer and 10 points deducted for wrong answer

Each deduction is -10 while each correct answer gives + 20

4 questions correctly and 11 incorrectly

= 4(20) + 11(-10)

= 80-110 = -30 points

Second round

7 correct, 8 incorrect

= 7(20) - 8(10)

= 140-80 = 60 points

4 0

3 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

3 years ago

Question is: Solve -7(x+6)=4(x+6)

Alina [70]

$\huge\boxed{x=-6}$

Hey there! Our goal here is to isolate the variable on one side of the equation.

$\begin{aligned}-7(x+6)&=4(x+6)&&\smash{\Big|}&&\textsf{Start with the original equation.}\\-7x+(-7)(6)&=4x+4(6)&&\smash{\Big|}&&\textsf{Distribute.}\\-7x-42&=4x+24&&\smash{\Big|}&&\textsf{Multiply.}\\-7x-4x&=24+42&&\smash{\Big|}&&\textsf{Move the terms.}\\-11x&=66&&\smash{\Big|}&&\textsf{Combine like terms.}\\x&=\boxed{-6}&&\smash{\Big|}&&\textsf{Divide both sides by $-11$.}\end{aligned}$

8 0

2 years ago

Read 2 more answers

For what values of a are the following expressions true?/a+5/=-5-a

katovenus [111]

Explanation:

The expression is given below as

$|a+5|=-5-a$

Concept:

We will apply the bsolute rule below

$\begin{gathered} if|u|=a,a>0 \\ then,u=a,u=-a \end{gathered}$

By applying the concept, we will have

$\begin{gathered} \lvert a+5\rvert=-5-a \\ a+5=-5-a,a+5=5+a \\ a+a=-5-5,a-a=5-5 \\ 2a=-10,0=0 \\ \frac{2a}{2}=\frac{-10}{2},0=0 \\ a=-5,0=0 \end{gathered}$

Hence,

The final answer is

$a\leq-5$

5 0

1 year ago