Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
Answer:
The answer is "
"
Step-by-step explanation:
The whole question can be found in the file attached.
Subtracting the 
from both sides of the equations:
<span>[-1,-1,1]
or
</span><span>[-2,-2,2]
</span>.....
Dot Product = 0
Answer:
Are the sides parallel?
Step-by-step explanation:
So you have to put 25 inside the blank box.
look at the attached picture
Hope it will help you
Good luck on your assignment
