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olga_2 [115]
3 years ago
6

4 less than the product of one and a number z

Mathematics
2 answers:
Doss [256]3 years ago
5 0

Answer:

it's 1z-4

Step-by-step explanation:

4 = 4

(less than) = subtraction

(product of) = multiplication

one = 1

Z = Z

do a switcheroo

which then becomes : (1)(z)(-)(4)

(product of) (one) and a (number z) = 1 multiplied by z

4 is less than = - 4 because it's less than

AleksAgata [21]3 years ago
3 0

Answer:

z - 4

Step-by-step explanation:

Step 1: Convert "4 less"

-4

Step 2: Convert "Product of one and a number z"

1 · z

z

Step 3: Combine

z - 4

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I need to know the of the blue line
8_murik_8 [283]

Step-by-step explanation:

if i pick (3,4) and (6,10)

the formula for gradient is difference in y divided by difference in x . therefore

10-4 divided by 6 - 3 equals to 6 divided by 3 = 2

the gradient is 2

8 0
2 years ago
-6+3y=12 solve for x
Roman55 [17]

Answer:

The answer is y=6

Step-by-step explanation:

Move the constant to the right side and change its sign

3y=12+6

Add the numbers

12 +6

3y=18

Divide both sides of the equation by 3

Which equals

Y=6

Hope that helps

5 0
4 years ago
Use the graph of f '(x) below to find the x values of the relative maximum on the graph of f(x):
Lana71 [14]

Answer:

You have relative maximum at x=1.

Step-by-step explanation:

-Note that f' is continuous and smooth everywhere. f therefore exists everywhere on the domain provided in the graph.

f' is greater than 0 when the curve is above the x-axis.

f' greater than 0 means that f is increasing there.

f' is less than 0 when the curve is below the x-axis.

f' is less than 0 means that f is decreasing there.

Since we are looking for relative maximum(s), we are looking for when the graph of f switches from increasing to decreasing. That forms something that looks like this '∩' sort of.

This means we are looking for when f' switches from positive to negative. At that switch point is where we have the relative maximum occurring at.

Looking at the graph the switch points are at x=0, x=1, and x=2.

At x=0, we have f' is less than 0 before x=0 and that f' is greater than 0 after x=0.  That means f is decreasing to increasing here. There would be a relative minimum at x=0.

At x=1, we have f' is greater than 0 before x=1 and that f' is less than 0 after x=1. That means f is increasing to decreasing here. There would be a relative maximum at x=1.

At x=2, we have f' is less than 0 before x=2 and that f' is greater than 0 after x=2. That means f is decreasing to increasing here. There would be a relative minimum at x=2.

Conclusion:

* Relative minimums at x=0 and x=2

* Relative maximums at x=1

3 0
3 years ago
30 ounces = ____lb ____oz
Darina [25.2K]
The answer is C. 1 lb 14 oz.
7 0
4 years ago
Read 2 more answers
Given the fu8nction f(x) = 2(x + 10), find x if f(x) = 24.<br><br> A) 68<br> B) 7<br> C) 17<br> D) 2
lyudmila [28]
F(x)=2(x+10)=24
2(x+10)=24
divide 2
x+10=12
minus 10
x=2
D
6 0
3 years ago
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