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Lisa [10]
3 years ago
7

A vat of milk has spilled on a tile floor. The milk flow can be expressed with the function r(t) = 4t, where t represents time i

n minutes and r represents how far the milk is spreading. The spilled milk is creating a circular pattern on the tile. The area of the pattern can be expressed as A(r) = πr2.
Part A: Find the area of the circle of spilled milk as a function of time, or A[r(t)]. Show your work. (6 points)

Part B: How large is the area of spilled milk after 4 minutes? You may use 3.14 to approximate π in this problem. (4 points)

Please help me i'm stuck :(
Mathematics
2 answers:
denis23 [38]3 years ago
4 0

Answer:

Part A:

Setting up the problem: A[r(t)] =  π (4t)^2

= Multiplying: A[r(t)] = 3.14 x 16t^2  

= Solving/Answer:  A[r(t)] = 50.24t^2

Part B: Area after 4 min of spilling = t=4

= r (4)= 4x4 =16

= Setting up the problem: A(16) = 3.14 x 16^2

= Multiplying:  A(16)= 3.14 x 256

= Solving/Answer: A(16) = 803.84

= The spilled area of milk after 4 min is 803.84.

Stells [14]3 years ago
3 0
Part A: Find the area of the circle of spilled milk as a function of time, or A[r(t)]
πr^2 = π(4t)^2  =π4^2*t^2=  16πt^2

Part B: A= 16π(4)^2 = 256π= 803.84

You should thank this guy, not me: https://www.peeranswer.com/question/55c927f10fa305466a8d3809

Hope this actually still helps! :)


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A regular hexagon has sides of 5 feet. What is the area of the hexagon? 12.5 ft 2 37.5 ft 2 25 ft 2 50 ft 2
nasty-shy [4]

Answer:  37.5\sqrt{3}

This value is exact. We can write this as 37.5*sqrt(3)

This approximates to roughly 64.9519

The units for the area are in square feet.

==========================================

Explanation:

Split the regular hexagon into 6 identical equilateral triangles.

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A = 0.25*sqrt(3)*x^2

A = 0.25*sqrt(3)*5^2

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4 0
3 years ago
Sean took 4 hours to travel from Town A to Town B at an
anzhelika [568]

Answer:

Tina's average speed  for the whole journey = 56 kmph

Step-by-step explanation:

Time taken by Sean to travel from Town A to Town B = 4 hours.

Average speed of Sean = 70 km/h

We have equation of motion, s = ut + 0.5 at²

Time, t = 4 hours.

Initial speed, u = 70 km/hr

Acceleration, a = 0 m/s²

Substituting

      s = ut + 0.5 at²

      s = 70 x 4 + 0.5 x 0 x  4²

       s = 280 km

Distance from Town A to Town B = 280 km

Tina took 1 hour more than Sean.

Time taken by Tina to travel from Town A to Town B = 4 +1 = 5 hours

We have equation of motion, s = ut + 0.5 at²

Time, t = 5 hours.

Displacement, s = 280 km

Acceleration, a = 0 m/s²

Substituting

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      280 = u x 5 + 0.5 x 0 x  5²

       u = 56 km/hr

Tina's average speed  for the whole journey = 56 kmph

8 0
3 years ago
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