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Elanso [62]
3 years ago
11

If Avery is willing to pay $10 for a pizza, Pia is willing to pay $13, and Sylvio is willing to pay $15, how much consumer surpl

us is achieved when the price of pizza is $12?
Mathematics
1 answer:
Mrrafil [7]3 years ago
4 0

Answer:

$4

Step-by-step explanation:

Total consumer surplus is given by the difference between the willingness to pay of each customer to the actual price of a good.

Since Avery is only willing to pay $10 and the pizza costs $12, Avery will not buy a pizza and should not be considered for consumer surplus.

Since Pia is willing to pay $13, and Sylvio is willing to pay $15, consumer surplus is:

S = (\$13-\$12)+(\$15-\$12)\\S=\$4

When the price of pizza is $12, a consumer surplus of $4 is achieved.

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What are the coordinates of point Q? HELPP QUICK !!!
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Answer:

The coordinates of point Q are \mathbf{(4,2\frac{1}{2})}

Step-by-step explanation:

The coordinates of point Q can be found looking at the graph

We need to find the value of x-coordinate and y-coordinate by looking at graph.

Check the value of x-coordinate that matches point Q similarly check the value of y-coordinate that matches point Q

Looking at the graph Point Q is at x=4 and y=2.5 or 2\frac{1}{2}

So,  The coordinates of point Q are \mathbf{(4,2\frac{1}{2})}

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3 years ago
What are the solutions for the equation 3(5x-1)^2=27
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See, pls, the suggested explanation:
3(5x-1)²=27 ⇔ 75x²-30x-24=0 ⇔ 25x²-10x-8=0 ⇒
\left[\begin{array}{ccc}x= \frac{5-15}{25} \\x= \frac{5+15}{25} \end{array}\right \ =\ \textgreater \  \   \left[\begin{array}{ccc}x=- \frac{2}{5} \\\ x= \frac{4}{5} \end{array}\right
4 0
3 years ago
Positive factors of 30
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1, 2, 3, 5, 6, 10, 15, 30

Step-by-step explanation:

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7 0
4 years ago
Estimate the following quantities without using a calculator. Then find a more precise result, using a calculator if necessary.
zubka84 [21]

Explanation:

a. It is so easy to double a number that no approximation is necessary.

  31,000 × 200 = 3.1×10⁴ × 2×10² = 6.2×10⁶ exactly

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b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

The approximation can be refined a bit by taking the ".2" into account:

  6.2×10³ × 5.2×10⁶ ≈ (6×5 + .2×(6+5))×10⁹

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Actual product: 3.224×10¹⁰.

For most purposes, the approximation is an adequate approximation, as it it within 10% of the actual value.

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c. 9×10⁶ -2.3×10⁴ ≈ 9×10⁶ approximately

A better approximation is to actually subtract an approximation of the smaller number:

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The actual value uses all of the digits of the smaller number:

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As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

_____

The accuracy required of an approximation, hence the work you expend improving accuracy, should depend on the need in the final application of the number. Often, approximations are used for budget or resource planning purposes where some "slop" is allowed or even expected.

They can also be used in engineering applications, where the error needs to be on the side of more safety (rather than less).

7 0
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