A tennis ball is dropped from 1.62 m above the
1 answer:
Answer:
-5.63 m/s
Explanation:
Given:
y₀ = 1.62 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2a (y − y₀)
v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.62 m)
v = -5.63 m/s
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