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2 years ago

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I need help, please help an object starts from rest at time t=0 and moves in the with constant acceleration. The object travels

3m from time t=1 to time t=2. what is the acceleration of the object?

1 answer:

vichka [17]2 years ago

4 0

<span>a=8(m/<span>sec2</span>).. i answered this earlier i think.</span>

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guapka [62]

Answer:

Pressure, P = 32666.66 Pa

Explanation:

It is given that,

Surface area of foot of Bimaba is 150 cm² or 0.015 m².

Her weight is 50 kg

We need to find the pressure does she exert on the ground, as she stands on her one foot. The force acting per unit area is called pressure. It can be given by :

$P=\dfrac{F}{A}\\\\P=\dfrac{mg}{A}\\\\P=\dfrac{50\times 9.8}{0.015}\\\\P=32666.66\ Pa$

So, the pressure is 32666.66 Pa.

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2 years ago

What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds? Please help

Deffense [45]

Answer:

oh umm it think its TV=11x*20s

Explanation:

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2 years ago

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garik1379 [7]

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3 years ago

Which of the following cannot be used to describe a longitudinal wave?

alex41 [277]

Answer:

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2 years ago

A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000

allochka39001 [22]

The final speed of the car at the given conditions is 30.1 m/s.

The given parameters:

<em>Mass of the car, m = 1700 kg</em>
<em>Velocity of the car, v = 21 m/s</em>
<em>Time of motion, t = 10 s</em>
<em>Additional energy provided by the engine, E₁ = 22,000 J</em>
<em>Energy used in overcoming friction, E₂ = 3,666.67 J</em>

The change in the energy applied to the car is calculated as;

$\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J$

The final speed of the car is calculated as follows;

$\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s$

Thus, the final speed of the car at the given conditions is 30.1 m/s.

Learn more about change in kinetic energy here: brainly.com/question/6480366

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2 years ago