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nadya68 [22]
3 years ago
13

IMPORTANT HELP HURRY

Mathematics
1 answer:
Zanzabum3 years ago
6 0
Let Bea = x
Therefore Andrew = x + 2
Chris = x - 3

Andrew * Chris = 66
(x + 2)(x - 3) = 66 Remove the brackets.
x^2 + 2x  - 3x - 6 = 66
x^2 - x - 6 = 66 Subtract 66 from both sides.
x^2 - x - 72 = 0
(x - 9)(x + 8) = 0
Find the possible values of Bea's age

x - 9 = 0
x = 9 That value works. She can be plus 9 years old.

x + 8 = 0
x = - 8. There's no way she can be - 8 years old
  
So Bea is 9. 
9 <<<<<< Answer
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Solve for x &amp; y solve x = 3 + yy = -2x + 9
sergey [27]

x = 3 + y Eqn(1)

y = -2x + 9​ Eqn(2)

Let us solve the system of equations with the substitution method

x - 3 = y (Subtracting 3 from both sides of the Eqn(1))

Replacing y = x - 3 in Eqn (2), we have:

x - 3 = -2x + 9

x = -2x + 9 + 3 (Adding 3 to both sides of the equation)

x + 2x = 9 + 3 (Adding 2x to both sides of the equation)

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x = 4

Replacing x=4 in Eqn(1), we have:

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The answers are:

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These are the systems of equations.

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