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zhuklara [117]
3 years ago
5

At the start of the softball season, the p players on the Hammerin' Homers softball team each

Mathematics
1 answer:
Lapatulllka [165]3 years ago
8 0
(18*7)+(20*10) * means times
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Who names their child peppermint patty, I mean the candy is good but you gotta be pretty devoted to it to do that.

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3 years ago
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Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

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2 years ago
What are the zeros of this function?<br><br> A) -8 <br> B) -9 and 10<br> C) -2 and 4 <br> D) 1
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C) -2 and 4 because it crosses over the x - axis
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In any triangle ABC, which of the relations
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ab+bc>can is the correct answer

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Question is in picture​
Pachacha [2.7K]

Answer:

I don't understand what should i answer.

The only thing I undrestood was that this is a relation which can be a function.

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3 years ago
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