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Andrew [12]
2 years ago
7

Why is a thermometer an example of a positive or negative number?

Mathematics
2 answers:
nikklg [1K]2 years ago
3 0

..........................

ch4aika [34]2 years ago
3 0

Answer:

It is a good example bc if its freezing its a negative if its not freezing its a positive

Step-by-step explanation:

numbers

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If the vertex of a parabola is at (2, 3) and the point (0, -1) is also on the parabola, find an equation for the parabola. Write
STALIN [3.7K]

Answer:

y=-1(x-2)^2+3

Step-by-step explanation:

W have been given that the vertex of a parabola is at (2, 3) and the point (0, -1) is also on the parabola. We are asked to find the equation of parabola in the form y=(x-h)^2+k.  

We know that vertex form of parabola in form y=a(x-h)^2+k, where (h,k) in vertex of parabola.  

Upon substituting coordinates of vertex, we will get:

y=a(x-2)^2+3

To find the value of a, we will substitute coordinates of point (0, -1) as:

-1=a(0-2)^2+3

-1=a(4)+3

-1=4a+3

-1-3=4a+3-3

-4=4a

\frac{-4}{4}=\frac{4a}{4}

-1=a

Therefore, our required equation would be y=-1(x-2)^2+3.

3 0
3 years ago
Suppose you have a $7-off coupon at a fabric store. You buy fabric that costs $9.50 per yeard. Write an equation that models the
galina1969 [7]

Answer:

y = 9.50x-7

Hope this helps!


8 0
3 years ago
The space shuttle releases a space telescope into orbit
sergey [27]

Answer: 68 m/s^{2}

Step-by-step explanation:

The acceleration a of the satellite can be calculated by the following equation:

V_{f}=V_{o}+at

Where:

V_{f}=1700 m/s is the final speed of the satellite

V_{o}=0 is the initial speed of the satellite (it was "stationary" before the release)

t=25 s is the time

Isolating a:

a=\frac{V_{f}}{t}

a=\frac{1700 m/s}{25 s}

Finally:

a=68 m/s^{2}

4 0
3 years ago
PLEASE HELP
Oksana_A [137]

Answer:

A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).

Hope it helped.

please mark brainliest

4 0
2 years ago
What is this problem -12=4(x-7)-8x
Fofino [41]

-12=4(x-7)-8x

One solution was found :

                  x = -4

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :


                    -12-(4*(x-7)-8*x)=0


Step by step solution :

Step  1  :

Equation at the end of step  1  :

 -12 -  (4 • (x - 7) -  8x)  = 0

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :


  4x + 16  =   4 • (x + 4)


Equation at the end of step  3  :

 4 • (x + 4)  = 0

Step  4  :

Equations which are never true :

4.1      Solve :    4   =  0

Hope this helps you, Have a nice day.

4 0
3 years ago
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