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pochemuha
3 years ago
10

6 less than the product of 3 and a number x

Mathematics
2 answers:
lora16 [44]3 years ago
7 0

Answer:

Less than is substraction

Product is multiplication

Therefore the expression is

6 - 3x

zloy xaker [14]3 years ago
6 0

Answer:

3x-6

Step-by-step explanation:

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2. Calculate the angular speed of the 26-inch bicycle rotating at 200 revolutions per minute. Express your answer in radians per
Alexus [3.1K]
The angular velocity for this problem is given by:
 Angular speed = 200 rev / min
 The first thing you should keep in mind is the following conversion:
 1 rev = 2π radians
 Applying the conversion we have:
 Angular speed = 200 * (2π)
 Rewriting:
 Angular speed = 200 * (2 * 3.14)
 Angular speed = 1256 radians / minutes
 Answer:
 
the angular speed is:
 
Angular speed = 1256 radians / minutes
4 0
3 years ago
How do I find the slope, domain, range and y intercept of y=-2x
Natasha2012 [34]

Slope is defined as the rate of change, in this case the change in y with respect to x. In standard form for a binomial linear equation, y = mx + b. The constants m and b are the slope and intercept, respectively. For your equation, the slope is -2 and the intercept is 0. The domain (possible values of x) for this graph is (-∞, ∞) and the range (possible values of y) is also (-∞, ∞).

5 0
3 years ago
1-cos^2 A / sec^2 A - tan^2 A
tiny-mole [99]
I hope this helps you



✔cos^2A+sin^2A=1


✔1-cos^2A=sin^2A

✔cos2A=cos^2A-sin^2A

✔sin2A=2.sinA.cosA


secA=1/cosA


tgA=sinA/cosA


sin^2A/1/cos^2A-sin^2A/cos^2A


sin^2A.cos^2A/cos2A

2.sin^2A.cos^2A/cos2A


sin2A.2.sin2A/cos2A


tg2A.2.sin2A


6 0
3 years ago
Find a pattern for the sequence. Use the pattern to show the next two terms.
quester [9]

Answer:

about this question the sequence of the pattern is according to the table of 12.

Step-by-step explanation:

Table of twelve is.

12

24

36

48

then the answer will be 60

<h3 />
6 0
2 years ago
Write 82.25% as a fraction in simplest form
tiny-mole [99]

The Answer To your Question is: 33/40

8 0
3 years ago
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