-x=5, |-x|=5.............................
Answer:
23.05 x 10.85
Step-by-step explanation:
Area of Rectangular Fence = L * W = 250
L * W = 250
W =
................................... (i)
Perimeter = 2L + 2W
Three sides cost 4 dollars per foot = 4(2L) + 4W
(The two lengths must be constructed with the 4 dollars materials)
Fourth side costs 13 dollars per foot = 13W
Cost = 4(2L) + 4W + 13W
C = 8L + 17W ...................................... (ii)
Substitute (i) into (ii)
C = 8L + 17 (
)
C = 8L +
Plotting this equation with L on the x-axis and cost on the y-axis
minimum cost will be when L ≈ 23.05 ft
W =
≈ 10.85 ft
minimum cost = 8(23.05) + 
minimum cost = 184.4 + 184.382
minimum cost ≈ 368.78 dollars
We want to find the greatest common factor of two given expressions.
The GCF is 15*a*b.
The two expressions are:
45*a^3*b^2 and 15*a*b
To find the greatest common factor, we can rewrite the first expression to get:
45*a^3*b^2 = (3*15)*(a^2*a)*(b*b)
Now remember that we can perform a multiplication in any order we want, so we can rearrange the factors to write this as:
(3*15)*(a^2*a)*(b*b) = (15*a*b)*(3*a^2*b)
Then we have:
45*a^3*b^2 = (15*a*b)*(3*a^2*b)
So we can see that 15*a*b is a factor of 45*a^3*b^2, then the GCF between 15*a*b and 45*a^3*b^2 is just 15*a*b.
If you want to learn more, you can read:
brainly.com/question/1986258
Answer:
B. 3/5
Step-by-step explanation:
I actually dont know how to explain srry
Answer:
In a system, the substitution method is one of the 3 main ways to solve a system and can be very efficient at times.
<u>Skills needed: Systems, Algebra</u>
Step-by-step explanation:
1) Let's say we are given two equations below:

We can use substitution here by substituting in for
in the second equation. This means we put in
for
in the 2nd equation so we only have
variables in the equation, allowing us to solve for
.
2) Solving it out:

We essentially substitute in that value as seen in step 1. Steps 2 and 3 are just simplifying the left side and allowing for us to solve. Step 4 is where we divide by -16 on both sides to solve for x. Step 5 and 6 show us solving for y using the value for x. We get 