Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
B.16 because 800 divided by 50 is 16
$16.67 would be the price of each pencil. You divide 50 by 3 and get 16.6 repeating so you round it up to 16.67
The equation would be y = 3x-3
