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vfiekz [6]
3 years ago
6

42 less than x is -50.

Mathematics
2 answers:
lutik1710 [3]3 years ago
6 0
The answer would be X = -8 because if 42 less than x is 50 than it has to be -8
STatiana [176]3 years ago
4 0
X-42=50
x=92

Hope this helps :)
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the perimeter of a rectangular garden is 84 feet. write and solve the system of equations that can be used to find the dimension
scoray [572]

Answer:

The length is 22.5 and the width is 19.5

Step-by-step explanation:

          2L + 2W = P

                     \/

          2L + 2W = 84

                     \/

W + 3 + W + 3 + W + W= 84

                     \/

          4W + 6 = 84

                     \/

                4W = 78

                     \/

     W = 19.5      L = 19.5 + 3 = 22.5

I hope this helps, have a nice day! :D

6 0
3 years ago
I Need Help thanks <br>:)?​
Feliz [49]

Answer:

6)  x = 40.5

8)  x = 16.5

Step-by-step explanation:

6) 45/x = 20/18

simplify and cross-multiply to get:

45/x = 10/9

10x = 405

x = 40.5

8) 22/8 = x/6

11/4 = x/6

4x = 66

x = 33/2

x = 16.5

8 0
3 years ago
If the measure of DAC is x and the measure of CAB is (2x – 30), what is the value of x? (HINT** remember how we label angles, th
Scorpion4ik [409]

Answer:

b

Step-by-step explanation:

∠ BAD = 90° and

∠ DAC + ∠ CAB = ∠ BAD, that is

x + 2x - 30 = 90

3x - 30 = 90 ( add 30 to both sides )

3x = 120 ( divide both sides by 3 )

x = 40 → b

6 0
3 years ago
I need the incomplete fraction answer for:<br> y=<br> z=<br> b=<br> Thx
sergejj [24]

Answer:

Y = 15sqrt(3)/4

Z = 15sqrt(3)/2

b = 45/4

Step-by-step explanation:

Sin(60) =Z/15

sqrt(3)/2 = Z/15

Z = 15sqrt(3)/2

Sin(30) = Y/Z

½ = Y/Z

Y = ½(15sqrt(3))/2 = 15sqrt(3)/4

Cos(30) = b/Z

sqrt(3)/2 = b/Z

b = 15sqrt(3)/2 × sqrt(3)/2

b = 45/4

sqrt is square root/radical

8 0
3 years ago
Read 2 more answers
What reason should kamal add to all of the question marks in order to completer the proof
brilliants [131]

Answer: The answers is alternate interior angles.


Step-by-step explanation:  First of all, the questions marks given in the figure are renamed in the attached figure as (a), (b), (c) and (d).

For (a): Since AC is parallel to A'C' and A'D is a transversal for these two parallel lines, so, ∠CDB' = ∠B'A'C', because these are alternate interior angles.

For (b): Since BC is parallel to B'C' and A'B' is a transversal, so ∠BEB' = ∠A'B'C', because these are alternate interior angles.

For (c): Since AB is parallel to A'B' and AD is a transversal, so ∠BAC = ∠CDB', because these are alternate interior angles.

For (d): Since AB is parallel to A'B' and BE is a transversal, so ∠ABC = ∠BEB', because these are alternate interior angles.

Thus, all the questions marks are the reasons that the given angles are equal because they are alternate interior angles.

5 0
3 years ago
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