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3 years ago

Simplify:$$\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}$$

Mathematics

2 answers:

bagirrra123 [75]3 years ago

8 0

Answer:

$5\sqrt{3}$

Step-by-step explanation:

$\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}=?\\\\1)\sqrt{8^2+15^2}=\sqrt{289}=17\\2)\sqrt{9^2+40^2}=\sqrt{1681}=41\\3)2\times17=34\\4)\sqrt{34+41}=5\sqrt{3}$

All Done!

Sati [7]3 years ago

4 0

Answer:

Your correct answer is 8.660254

Step-by-step explanation:

√2√82 + 152 + √92 + 402 = 8.660254

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Which function has a range of y<3? y=3(2) y=2(3) O y=-(2)* +3 O y= (2)* - 3

VARVARA [1.3K]

option C is correct.

Step-by-step explanation:

If a function is defined as

$f(x)=a^x$ where, a>0, then the range of the function is greater than 0.

$a^x>0$ .... (1)

Option A: Using inequity (1),

$2^x>0$

Multiply both side by 3.

$3(2^x)>0$

The range of first function is y>0. Therefore option A is incorrect.

Option B: Using inequity (1),

$3^x>0$

Multiply both side by 2.

$2(3^x)>0$

The range of second function is y>0. Therefore option B is incorrect.

Option C: Using inequity (1),

$2^x>0$

Multiply both side by -1.

$-2^x$

Add 3 on both the sides.

$-2^x+3$

$y$

The range of first function is y<3. Therefore option C is correct.

Option D: Using inequity (1),

$2^x>0$

Subtract 3 from both the sides.

$2^x-3>-3$

$y>-3$

The range of second function is y>-3. Therefore option D is incorrect.

7 0

3 years ago

Five of Teddy’s six cousins can

Sliva [168]

Answer: 0.83

Step-by-step explanation:

The fraction of Teddy's cousins what can do push-ups is $\frac{5}{6}$ . We get this fraction because the problem states that 5 of Teddy's 6 cousins can do 15 push-ups. Now that we have our fraction, we divide to get our decimal.