ABC = 408
C + 7 = B
A + 5 = B
B - 7 + B - 5 + B = 408
3B - 12 = 408
+ 12 = +12
3B = 420
/3 = /3
B = 120
A = 115
C = 113
The answer is A = 115, Abel has $ 115
Answer:
I think it is C if you have a base nuber of 7 that is at least halfway acros it it can not be over 100
Step-by-step explanation:
Answer: SAS
Step-by-step explanation:
There is an angle B or D and the sides being the 26, 21, and 32! (Sorry if I get it wrong)
