Answer:
3x
Step-by-step explanation:
50 mi/hr × (1 hr / 60 min) × (200 gal / 500 mi) = ⅓ gal/min
(⅓ gal/min) × (t min) = x gal
t = 3x
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
You should subtract left sides and right sides in order to make y disappeared
and you will have the following:
y - y = (x - 6) - (3x - 8) => 0 = x - 6 - 3x - 8 => 0 = -2x - 14 =>
2x = -14 => x = -14/2 = -7
Now you can use -7 in the system and you will get y
y = -7 - 6 = -13
So your answers will be:
x=-7 and y=-13
