(5x10,000) +(2x100) +(9x1) +(3x1/1000)

To which subsets does 15/5 belong?

Alexus [3.1K]

Answer:

Whole, natural, integer, rational, real

Step-by-step explanation:

15/5 can be rewritten as 3.

7 0

3 years ago

What is the minimum number of 60 passenger buses needed to transport 200 students?

Marina86 [1]

You would need four busses

4 0

3 years ago

The value, V, of Kalani’s stock investments over a time period, x, can be determined using the equation v=750(0.80)-x. What is t

Snowcat [4.5K]

The rate of increase and decrease associated with Kalani's stock investments would be a 25% per year increase.

Therefore, the correct option of all the answer choices you listed is: C.

6 0

4 years ago

Read 2 more answers

the ratio of an equal side of an isosceles triangle to it's base is 3:4 and it's perimeter is 60 cm. find its area.

Ann [662]

Answer:

160.10 (2 dp.)

Step-by-step explanation:

So when you have ratio questions, similar to this one, you should always add up the parts.

This question actually involves many steps.

We are trying to find the length of all the sides first, we already know that the 3 sides add up to 60cm.

The triangle is made up of 3:3:4, as it has two equal sides and one base. The total parts is 3 + 3 + 4 = 10.

To find how much one part is. we divide the perimeter by the total parts

60/10 = 6

If one part equals 6, then we just multiply by the number of parts to find the entire length, this means that the sides equal 6 x 3 = 18 and the base is

6 x 4 = 24.

Now, we need to find the height in order to find the area of the triangle, to find the height we will be using Pythagoras theorem.

Pythagoras theorem states that a^2 + b^2 = c^2

If we split the triangle in half down the middle, we have a right angle triangle, we know the length of hypotenuse and one side.

The hypotenuse would be one of the equal sides of the isosceles triangle, which is 18cm, and the other side would be half of the base which is 24/2 = 12cm , as we are splitting the isosceles triangle down the middle.

Now we can use the theorem to find the height:

a = height

b = 12

c = 18

Formula:

h^2 + 12^2 = 18^2

rearrange and simplify:

18^2 - 12^2 = h^2

324 - 144 = h^2

180 = h^2

h = root 180 (we will leave this as a surd as it is not a perfect square)

Now that we know the height we can find the area, the formula of a triangle is half x base x height:

1/2 x 24 x root 180

= 160.10 (2 dp.)

Hope this helps,

Cate

5 0

3 years ago

g A lawyer commutes daily from his suburban home to his midtown office. The average time for a one-way trip is 24 minutes, with

rodikova [14]

Answer:

a) 85.31%

b) 56 minutes

c) 17 days

d) 0.1721

Step-by-step explanation:

In order to make the calculations easier, let's <em>standardize the curve</em> by doing the change

$Z=\frac{X-\mu}{\sigma}$

where $\mu$ is the average trip-time and $\sigma$ the standard deviation and

P(X≤ t) is the probability that the trip takes less than t minutes.

a)

Here we are looking for the value of P(X>20).

For X=20 we have Z = (20-24)/3.8 = -1.05

So, we want the area under the standard normal curve for Z > -1.05

that we can compute either using a table or a computer and we find this area equals 0.8531

So, he arrives late to work 85.31% of the times.

(See picture 1 attached)

b)

In this case we are looking for a value t of time such that

P(X≥ t) = 20% = 0.2

So, we are seeking a value Z such that the area under the normal curve to the left of Z equals 0.2

By using a table or a computer we find Z = 0.842

(See picture 2 attached)

By inserting this value in the equation on standardization

$0.842=\frac{X-24}{38}\Rightarrow X=38*0.842+24=55.996$

So 20% of the longest trips takes 55.996 ≅ 56 minutes

c)

Since the average of days he arrives late is 85.31%, it is expected that in 20 work days he arrives late 85.31% of 20, which equals 17 days.

d)

Since the probability that he does not arrive late is 1-0.8531 = 0.1469 and the probability of arriving early is independent of the previous trip,

the probability of arriving early n days in a row is

0.1496*0.1496*...*0.1496 n times and

the probability of being early most than 10 trips in 20 days is

$(0.1469)+(0.1469)^2+(0.1469)^3+...+(0.1469)^10=0.1721$

3 0

3 years ago

(5x10,000) +(2x100) +(9x1) +(3x1/1000)​

(5x10,000) +(2x100) +(9x1) +(3x1/1000)