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erma4kov [3.2K]
2 years ago
15

(

Mathematics
1 answer:
Sladkaya [172]2 years ago
8 0

The expression is simplified to give -7x^2 - 11x

<h3>What are algebraic expressions?</h3>

Algebraic expressions are expressions that contains variables, constants, factors and coefficients.

They are also made up of arithmetic operations such as addition, subtraction, multiplication, division, etc.

From the information given, we have;

(- x^2 - 5x ) - ( 6x^2 + 5x)

expand the bracket

-x^2 - 5x - 6x^2 - 5x

collect like terms

-7x^2 - 11x

Thus, the expression is simplified to give -7x^2 - 11x

Learn more about algebraic expressions here:

brainly.com/question/4344214

#SPJ1

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I don’t know what the answer is
stellarik [79]
Cubes and then three dimensional
3 0
3 years ago
Can someone please help?
Nostrana [21]

Answer:

\frac{108}{125}

Step-by-step explanation:

\frac{3}{5}*\frac{25}{24}= \frac{72}{125}

\frac{72}{125}÷\frac{2}{3}=\frac{108}{125}

Hope this helps you!

3 0
3 years ago
Evaluate 5-44• (-0.75) - 18 ÷ 2/3 • 0.8 + (-4/5)​
Marianna [84]

Answer:

15.6.

Step-by-step explanation:

5-44• (-0.75) - 18 ÷ 2/3 • 0.8 + (-4/5)

= 5 + 33 - 27*0.8 - 0.8

= 5 + 33 -21.6 - 0.8

= 15.6.

4 0
3 years ago
Prove that sin^2A/cos^2A + cos^2A/sin^2A = 1/cos^2A*sin^2A - 2
jenyasd209 [6]

Answer:

prove that:

Sin²A/Cos²A + Cos²A/Sin²A = 1/Cos²A Sin²A - 2

LHS = \frac{Sin^2A}{Cos^2A} + \frac{Cos^2A}{Sin^2A}

Cos

2

A

Sin

2

A

+

Sin

2

A

Cos

2

A

= \begin{lgathered}= \frac{Sin^4A + Cos^4A}{Cos^2A . Sin^2A}\\\\Using\: a^2 + b^2 = (a+b)^2 - 2ab\\\\a = Cos^2A \: \& \:b = Sin^2A\\\\= \frac{(Sin^2A + Cos^2A)^2 - 2Sin^2A Cos^2A}{Cos^2A Sin^2A} \\\\Sin^2A + Cos^2A = 1\\\\= \frac{1 -2Sin^2A Cos^2A}{Cos^2A Sin^2A}\end{lgathered}

=

Cos

2

A.Sin

2

A

Sin

4

A+Cos

4

A

Usinga

2

+b

2

=(a+b)

2

−2ab

a=Cos

2

A&b=Sin

2

A

=

Cos

2

ASin

2

A

(Sin

2

A+Cos

2

A)

2

−2Sin

2

ACos

2

A

Sin

2

A+Cos

2

A=1

=

Cos

2

ASin

2

A

1−2Sin

2

ACos

2

A

\begin{lgathered}= \frac{1}{Cos^2A Sin^2A} - 2\\\\= RHS\end{lgathered}

=

Cos

2

ASin

2

A

1

−2

=RHS

LHS=RHS

4 0
3 years ago
Read 2 more answers
A relation is
insens350 [35]

Answer:

its 2

Step-by-step explanation:

can i get brainliest

4 0
3 years ago
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