Answer:
7.
green blocks represent n
and normale digits (plus green) are orange
Anne: 1 orange block and increasing 2 green blocks from 2 sides
Sanjay: one line of green and orange line plus 1
Robert: 2 times the amount of green blocks on both lines with 1 orange block on right path
9.
a.y = 6x
b.y = 2^x
c.y = x+10
10.
a. 2 green blocks and 2 orange blocks
c. 3 green blocks and 1 orangle blocks
b. 4 green blocks
d.2 green blocks and 1 orange block
Step-by-step explanation:
for 10, it doesn't really matter
Answer:
The 2 pound bag of gummy bears
Step-by-step explanation:
You do 1.5/4.35 which = 2.9 the 2.9 is $2.90 per pound
Then, you do 5.3/2 which = 2.6 this 2.6 is $2.60 per pound
$2.60 < $2.90 there for the 2 pound bag of gummy bears is the better deal
Answer:
<h2><em>
2x-4</em></h2>
Step-by-step explanation:
Area of a rectangle = Length * Width
Given parameters
Area A = 8x2 – 10x – 12
Length of the rectangle = 4x+3
Required
Width of the rectangle.
Substituting the given parameters into the formula
8x2 – 10x – 12 = (4x+3)*width
width = 8x2 – 10x – 12
/4x+3
S
Factorizing the numerator
8x² – 10x – 12
= 2(4x²-5x-6)
= 2(4x²-8x+3x-6)
= 2(4x(x-2)+3(x-2))
= 2(4x+3)(x-2)
Width = 2(4x+3)(x-2)/4x+3
Width = 2(x-2)
Width = 2x-4
<em>Hence the width of the rectangle is 2x-4</em>
<u>Options</u>
- Counting rule for permutations
- Counting rule for multiple-step experiments
- Counting rule for combinations
- Counting rule for independent events
Answer:
(C)Counting rule for combinations
Step-by-step explanation:
When selecting n objects from a set of N objects, we can determine the number of experimental outcomes using permutation or combination.
- When the order of selection is important, we use permutation.
- However, whenever the order of selection is not important, we use combination.
Therefore, The counting rule that is used for counting the number of experimental outcomes when n objects are selected from a set of N objects where order of selection is not important is called the counting rule for combinations.