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3 years ago

How to calculate the area of a triangle with the hypotenuse as an arc?

Mathematics

1 answer:

agasfer [191]3 years ago

7 0

The arc of the triangle

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Help with this question ??

salantis [7]

Answer:

15 units per unit

Step-by-step explanation:

From the graph we can easily tell that y increases from 0 to 15 as x increases from 2 to 3.

Thus, the average rate of change of f(x) on the interval [2, 3] is:

1 15 - 0 15 units

--------- * ----------- = -------------- = 15 units (rise) per unit (run).

3 - 2 1 1

6 0

3 years ago

Which term is a perfect square of the root 3x4?<br>

Volgvan

Answer:

Step-by-step explanation:

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3 years ago

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Find the volume<br> Pls don’t answer if you don’t know the correct answer.

natulia [17]

can i just get a thank you ? lol

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3 years ago

You roll a 6 sided cube, what is the probability of rolling a multiple of 2 or a number greater than 3?

vova2212 [387]

The probability of rolling a multiple 2 or a number greater than 3 is 1/3

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3 years ago

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A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

4 years ago