The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
c. 4.6
21 X .22= 4.6
Calculating the variance requires finding the product of 21 and 22%. To make this easier we convert 22% into it's decimal form and construct the equation. To back check this answer we can use 10% of 21 voters which equals 2.1% then double that amount to reach 4.2%, knowing that we now have a close approximation of the variance we can eliminate answers a, b, and d, leaving c as the only logical choice.
Where you stop/finish. hope that helps :)
Answer:
Step-by-step explanation:
(7/12) of 840 attended the concert:
(7/12)*(840) = 490 students attended the Spring Concert.
(840 - 490) = 350 did not attend
(350/840) is the fraction of students who did not attend. This can be reduced to (35/84)
(350/840) = 0.4167 or 41.67% did not attend.
Answer:
$820
Step-by-step explanation:
Total = Equipment + Props
T = 369 + 0.55T
0.45T = 369
<u>T = 820</u>
I hope this helps!
