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2 years ago

Which ratio below is equivalent to the ratio 7 : 350

Mathematics

1 answer:

Elden [556K]2 years ago

5 0

Answer:

the ratio is 1:50 i don't see anymore ratio underneath

Step-by-step explanation:

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Can someone please help me with this question

lisov135 [29]

Is letter B hope it help

5 0

3 years ago

Read 2 more answers

Fast I will give brainlist The total number of seats in a movie theater is calculated by adding the area of the upper section gi

Blizzard [7]

Answer:

(888)

Step-by-step explanation:

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5 0

2 years ago

Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant

son4ous [18]

The chain rule states that

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

Since $\ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2)$ , you have

$\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}$

and

$\dfrac{\mathrm dx}{\mathrm dt}=\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t$

Also, since $x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t$ , the derivative is

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\tan t$

4 0

2 years ago

PLEASE HELP ME ASAP I WILL MARK YOU AS BRILLIANT please help with these three

GalinKa [24]

Answer:

26: x=34

28: x=17

30: m=30

Step-by-step explanation:

26: 2x+22=90

subtract 22

2x=68

divide by 2

x=34

28: 18+3x+21=90

add 18 and 21

3x+39=90

subtract 39

3x=51

divide by 3

x=17

30: 43+87+m+20=180

add 43 and 87 and 20

m+150=180

subtract 150

m=30

6 0

3 years ago

The number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the

liq [111]

Answer:

Option B. 59%

Explanation:

The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:

$A(t)=136(1.123)^{4t}$

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:

$rate=(1.123)^{4t}=(1.123)^4=1.590$

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

8 0

3 years ago