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Delvig [45]
3 years ago
10

(4j3 - 7j + 2s3 ) - ( - 12j3 - 8j )

Mathematics
1 answer:
OLga [1]3 years ago
7 0

Answer:

-8j^3+j+2s^3

Step-by-step explanation:

The trick here is to consider j^3, j, and s^3 as separate variables.

(4j^3-7j+2s^3)-(-12j^3-8j)

4j^3-7j+2s^3+12j^3+8j

4j^3+12j^3-7j+8j+2s^3

16j^3+j+2s^3

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