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konstantin123 [22]
3 years ago
6

Wasserman (1989) studied a process for the manufacturing of steel bolts. Historically, these bolts have a mean thickness of 10.0

mm and a standard deviation of 1.6 mm. In a quality check, the engineer has a sample of 5 randomly selected and measured.
Assuming a near-normal distribution, what are the mean and standard deviation of the sample mean of these quality checks?
Mathematics
1 answer:
zalisa [80]3 years ago
7 0

Answer:

The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.

Step-by-step explanation:

To solve this question, we use the central limit theorem.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 10, \sigma = 1.6, n = 5, s = \frac{1.6}{\sqrt{5}} = 0.7155

The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.

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What is 3/4 doubled? Is it 6/8 or 1 2/4?
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Answer:

1 2/4

Step-by-step explanation:

3/4 doubled is 2(\frac{3}{4} )=\frac{3}{2}

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1 \frac{2}{4} =\frac{6}{4} =\frac{3}{2}

Therefore,

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3 years ago
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7 0
3 years ago
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OLEGan [10]

Answer/Step-by-step explanation:

The following steps to solve equation given by join are shown below including the property of numbers applied for each reasons:

4(2a + 3) = -3(a - 1) + 31 - 11a ----› Given

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4*2a + 4*3 = -3*a -3*-1 + 31 - 11a

8a + 12 = -3a + 3 + 31 - 11a ----› Distributive property

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8a + 12 = 34 - 14a ---› Combining like terms

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22a = 22 ----› subtraction property of equality

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Answer:

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n = 12

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3 years ago
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