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konstantin123 [22]
3 years ago
6

Wasserman (1989) studied a process for the manufacturing of steel bolts. Historically, these bolts have a mean thickness of 10.0

mm and a standard deviation of 1.6 mm. In a quality check, the engineer has a sample of 5 randomly selected and measured.
Assuming a near-normal distribution, what are the mean and standard deviation of the sample mean of these quality checks?
Mathematics
1 answer:
zalisa [80]3 years ago
7 0

Answer:

The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.

Step-by-step explanation:

To solve this question, we use the central limit theorem.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 10, \sigma = 1.6, n = 5, s = \frac{1.6}{\sqrt{5}} = 0.7155

The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.

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Answer:

Distance around the pool = 162.8 feet

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Step-by-step explanation:

Distance around the swimming pool = Perimeter of the pool

Perimeter of the pool which is a composite figure will be,

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= πr + 2×(length of the pool) + width of the pool

= 3.14×(10) + 2×40 + 20

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Area of the pool = Area of the semicircle + Area of the rectangular pool

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Step-by-step explanation:

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