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Aleksandr-060686 [28]
2 years ago
10

If y(x+1)=a,then x=?​

Mathematics
2 answers:
snow_lady [41]2 years ago
5 0
If y(x - 1) = z then x = A. y - z B. z /y + 1 C. y(z - 1) D.
ArbitrLikvidat [17]2 years ago
3 0

GIVEN: y(x−1)=zy(x−1)=z

Divide both sides by y to get: x−1=zyx−1=zy

Add 1 to both sides to get: x=zy+1

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Find and simplify the expression if f(x)=x^2-10.<br><br> f(4+h)-f(4)=
11111nata11111 [884]

f(4+h)-f(4)=(4+h)^2-10-(4^2-10)\\f(4+h)-f(4)=16+8h+h^2-10-16+10\\f(4+h)-f(4)=h^2+8h

8 0
2 years ago
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Find the m &lt; VXW down below
zvonat [6]

Answer:

Step-by-step explanation:

5 0
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5) Tom knows that in his school 10 out of every 85 students are left-handed.
Alina [70]

Answer:

yes well hi and hit the WOW

Step-by-step explanation:

7 0
2 years ago
Solve the compound inequality. Graph the solution<br> -2 ≤ 2x – 4 &lt; 4
Ulleksa [173]
-2 \ \textless \ = 2x - 4 \ \textless \  4 

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5 0
3 years ago
Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4
vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

c^2 = 4^2 + 6^2

c^2 = 16 + 36

c^{2} = 52

Pythagoras' theorem for the middle one :

b^{2} = 6^{2} + a^{2}

Pythagoras' theorem for the biggest one :

(4+a)^2 = c^2 + b^2

16 + 8a + a^2 = 52 + b^2

Using the formula before (for b^2) it becomes :

16 + 8a + a^2 = 52 + (6^2 + a^2)

16 + 8a + a^2 = 52 + 6^2 + a^2

16 + 8a = 52 + 6^2

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

a = \frac{72}{8}

a = 9

Verifying :

b^2 = 6^2 + a^2

b^2 = 36 + 81

b^2 = 117

b^{2} = 117

The biggest one :

(4+a)^2 = c^2 + b^2

(4+9)^2 = 52 + 117

13^2 = 169

True

8 0
2 years ago
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