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Aleksandr-060686 [28]

2 years ago

10

If y(x+1)=a,then x=?

2 answers:

snow_lady [41]2 years ago

5 0

If y(x - 1) = z then x = A. y - z B. z /y + 1 C. y(z - 1) D.

ArbitrLikvidat [17]2 years ago

3 0

GIVEN: y(x−1)=zy(x−1)=z

Divide both sides by y to get: x−1=zyx−1=zy

Add 1 to both sides to get: x=zy+1

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Find and simplify the expression if f(x)=x^2-10.<br><br> f(4+h)-f(4)=

11111nata11111 [884]

$f(4+h)-f(4)=(4+h)^2-10-(4^2-10)\\f(4+h)-f(4)=16+8h+h^2-10-16+10\\f(4+h)-f(4)=h^2+8h$

8 0

2 years ago

Read 2 more answers

Find the m < VXW down below

zvonat [6]

Answer:

Step-by-step explanation:

5 0

2 years ago

5) Tom knows that in his school 10 out of every 85 students are left-handed.

Alina [70]

Answer:

yes well hi and hit the WOW

Step-by-step explanation:

7 0

2 years ago

Solve the compound inequality. Graph the solution<br> -2 ≤ 2x – 4 < 4

Ulleksa [173]

$-2 \ \textless \ = 2x - 4 \ \textless \ 4$

$-2+4\ \textless \ 2x\ \textless \ 4+4
 
$ $Add \ 4 \ to \ the \ whole \ equation$

$
2\ \textless \ 2x\ \textless \ 8
 
$ $Simplify \ inequality$

$1\ \textless \ x\ \textless \ \dfrac{8}{2}$ $Divide \ the \ whole \ equation \ by \ 2$

$
1\ \textless \ x\ \textless \ 4
 
$ $= (1,4)$

5 0

3 years ago

Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

$c^2 = 4^2 + 6^2$

$c^2 = 16 + 36$

$c^{2}$ = 52

Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

$a = \frac{72}{8}$

a = 9

Verifying :

$b^2 = 6^2 + a^2$

$b^2 = 36 + 81$

$b^2 = 117$

$b^{2}$ = 117

The biggest one :

$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

8 0

2 years ago