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3 years ago

What is the completely factored form of 8x^2 -50

Mathematics

1 answer:

dezoksy [38]3 years ago

4 0

<span>8x^2 -50
= 2(4</span><span>x^2 - 25)
= 2(2x + 5)(2x - 5)

hope it helps </span>

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Jenny bought 0.18lb of penny candy. Will bought 0.9lb of penny candy. Who bought more?

Natasha2012 [34]

Answer:

will

Step-by-step explanation:

jenny bought 18/100

will bought 9/10

3 0

2 years ago

The graph of y = |x| is shifted to the left by 6 units.

Gnom [1K]

Answer:

D, y= |x+6|

When a graph is shifted to the left, you add the shifted value to the x value in function notation.

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2 years ago

According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women

blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : $P(X=r) =^nC_r p^r q^{n-r}$

At x = 2

$P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}$

$P(X=2) =8.8009 \times 10^{-7}$

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So, $P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})$

$P(X=r) =9.9439 \times 10^{-6}$

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

$={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=0.2360$

8 0

3 years ago

3+5i/-2+3i perform operation

melisa1 [442]

Answer:

$\dfrac{9}{13}-\dfrac{19}{13}i$

Step-by-step explanation:

Remember $i^2=-1$

You are given the fraction $\dfrac{3+5i}{-2+3i}$

First, multiply the numerator and the denominator by -2-3i:

$\dfrac{3+5i}{-2+3i}=\dfrac{(3+5i)(-2-3i)}{(-2+3i)(-2-3i)}=\dfrac{(3+5i)(-2-3i)}{(-2)^2-(3i)^2}=\dfrac{(3+5i)(-2-3i)}{4-9i^2}=\dfrac{(3+5i)(-2-3i)}{4+9}$

This gives you 13 in denominator, now multiply two complex numbers in numerator:

$(3+5i)(-2-3i)=-6-9i-10i-15i^2=-6-19i+15=9-19i$

Thus, the initial fraction is

$\dfrac{9-19i}{13}=\dfrac{9}{13}-\dfrac{19}{13}i$

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2 years ago

What is the scale factor of ALMN TO AOPO?

pochemuha

Answer:

There is a scale factor of 1

Step-by-step explanation:

the ratio 1:1 means that there is no difference between the two triangles, and that they are congruent.

4 0

3 years ago

Read 2 more answers