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3 years ago

Please explain question nine, I’m struggling with math and I wanna dieeee

Mathematics

1 answer:

-BARSIC- [3]3 years ago

7 0

It’s 17 because the ranking of the two teams add up to 17

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2 years ago

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2 years ago

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2 years ago

Solve the equation to find x. <br> 4x +12 = 96

wel

Answer:

x=21

Step-by-step explanation:

4x+12=96

subtract 12 from both sides

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2 years ago

Read 2 more answers

Please help!

777dan777 [17]

Answer:

$\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}$

Step-by-step explanation:

Use formulas for the volumes:

$V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.$

1. When r=1,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.$

2. When r=2,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.$

3. When r=3,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.$

4. When r=4,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.$

5. When r=5,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.$

Note that for all r,

$\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.$

8 0

3 years ago

Read 2 more answers