Answer:
sorry I can't help you because the diagram is not there and I can't get the answer without it
The figure consists of a rectangle and a circle.
first lets find the sides of the triangle
sides of the triangle are 4+4=8 and 3+1=4
therefore area of the rectangle is 8*4=32
now area of semicircle =πr^2/2 = π2^2/2=2π=6.3
we have to add the area of rectangle with the area of semicircle
this is because it the given figure no part of area of circle and rectangle are in common.
therefore total area of given figure = 32+6.3=38.3
Answer: 55.56
Step-by-step explanation:
Let the unknown number be k
(45 x k) / 100 = 25
45k/100 = 25
multiply both sides by 100
45k = 25 x 100
45k = 2500
divide both sides by 45
k = 2500/45
k = 55.56
Area = the top semicircle + the rectangle AEBD
= 1/2 pi*6^2 + 6*12 = 128.55 cm^2 to nearest 100th
Perimeter = 6pi + 12 + 2 pi * 3 = 49.70 cm
Answer:
135°
Step-by-step Explanation:
==>Given:
An inscribed quadrilateral ABCD with,
m<A = (3x +6)°
m<C = (x + 2)°
==>Required:
measure of angle A
==>Solution:
First, let's find the value of x.
Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.
Therefore, this means m<A + m<C = 180°
Thus, (3x+6) + (x+2} = 180
3x + 6 + x + 2 = 180
Collect like terms:
3x + x + 6 + 2 = 180
4x + 8 = 180
Subtract 8 from both sides:
4x + 8 - 8 = 180 - 8
4x = 172
Divide both sides by 4:
4x/4 = 172/4
x = 43
We can now find m<A = (3x + 6)°
m<A = 3(43) + 6
= 129 + 6
measure of angle A = 135°