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Brut [27]
3 years ago
5

Scott asked Bud if

Mathematics
2 answers:
Sliva [168]3 years ago
7 0
I think B since it’s a proper grammatical question to ask I guess
djverab [1.8K]3 years ago
4 0
I think you used the wrong subject.

your answer is B though.
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What is the height of cone S?
balu736 [363]

Answer:

12 cm

Step-by-step explanation:

First, we find the scale factor from cone S to cone T.

ratio of volumes = (vol of T)/(vol of S) = (6144 pi cm^3)/(768 pi cm^3) = 8

The ratio of the volumes is 8:1

The scale factor, which is the ratio of linear dimensions (height, radius, etc.), is the cubic root of the ratio of the volumes.

scale factor = cubic root of 8 = 2

The height of cube T is 24 cm, so the height of cube S is 24 cm/2 = 12 cm.

4 0
4 years ago
Read 2 more answers
The front of Rosie's house is similar in shape to the front of Sparky's doghouse. The base of the doghouse is 6 feet and the hei
Shtirlitz [24]

Answer:

33feet

Step-by-step explanation:

If the base of the doghouse is 6 feet and the height is 5 feet, we can write;

6 feet base = 5 feet height

To get the length of the base if the height is 27.5feet

x feet base = 27.5 feet high

Divide both expressions

6/x = 5/27.5

5x = 6 * 27.5

5x = 165

x = 165/5

x = 33ft

Hence the length of its base will be 33feet

4 0
3 years ago
Pls helphelpepelsjjejdkdkdjf
Yuki888 [10]

Answer:

bbb

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Step-by-step explanation:

8 0
3 years ago
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Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that
aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

A\cap B={HH}

B\cap C={HH}

A\cap C={HH}

P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

P(A)=\frac{2}{4}=\frac{1}{2}

Number of favorable cases to event B=2

Number of favorable cases to event C=2

P(B)=\frac{2}{4}=\frac{1}{2}

P(C)=\frac{2}{4}=\frac{1}{2}

If the two events A and B are independent then

P(A)\cdot P(B)=P(A\cap B)

P(A\cap)=\frac{1}{4}

P(B\cap C)=\frac{1}{4}

P(A\cap C)=\frac{1}{4}

P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}

P(B)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(B)=P(A\cap B)

Therefore, A and B are independent

P(B)\cdot P(C)=P(B\cap C)

Therefore, B and C are independent

P(A\cap C)=P(A)\cdot P(C)

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0
3 years ago
Find the value of x - Step by step answer please
Ugo [173]

Answer:

x = -2

Step-by-step explanation:

Given :

\frac{8}{x+1} = \frac{-16}{x+4}

=============================================================

Cross multiplying the terms :

⇒ 8 (x + 4) = -16 (x + 1)

⇒ 8x + 32 = -16x - 16

⇒ 24x = -48

⇒ x = -2

5 0
2 years ago
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