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Jobisdone [24]
3 years ago
15

What -8 and then minus -3 and then plus 10 and then times 2

Mathematics
2 answers:
slamgirl [31]3 years ago
5 0
15

Hope this helped :)
Advocard [28]3 years ago
4 0
-2...
hope this helps and HAGD!
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What’s the answer for this question?
qaws [65]

Answer:

d.

Step-by-step explanation:

you would put 4 in the x places and 2 in the yplaces and then you would distribute 4^2 +3(2)/4(2)

16+6/2=22/8=2 3/4

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3 years ago
3x-7&gt;5<br> Find the solution, please show your work. Thank You!1
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To find x just change the <span>> to a =
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2 years ago
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How would you know if these are a positive or a negative 0,1) and (-3,6).
Ipatiy [6.2K]
Negative has the little dash in front of it

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3 years ago
A hotel purchases 150 bath towels for 1,800. The hotel later purchases 40 more bath towels for x. If the unit cost remains the s
olga2289 [7]
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8 0
3 years ago
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he number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.02
Yakvenalex [24]

Answer:

a) 98.01%

b) 13.53\%

c) 27.06%

Step-by-step explanation:

Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2  

If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,

P(k)= \frac{0.2^ke^{-0.2}}{k!}

a)

In this case, we are looking for P(0)

P(0)= \frac{0.2^0e^{-0.2}}{0!}=e^{-0.2}=0.9801=98.01\%

So, the probability that a car has no flaws is 98.01%

b)

Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.

Now P(k) is the probability that 10 cars have k flaws and  

P(k)= \frac{2^ke^{-2}}{k!}

and  

P(0)= \frac{2^0e^{-2}}{0!}=0.1353=13.53\%

And the probability that 10 cars have no flaws is 13.53%

c)

Here, we are looking for P(1) with P defined as in b)

P(1)= \frac{2^1e^{-2}}{1!}=2e^{-2}=0.2706=27.06\%

Hence, the probability that at most one car has no flaws is 27.06%

6 0
3 years ago
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