Answer:
The distance, in feet, between the strip = 12 feet.
Step-by-step explanation:
From the figure attached in relation with the question, we can deduce that crosswalk is a parallelogram where
CD/AB = CE/AE
CD = 40
CE = 50
AE = 15
Let AB = x
50x = 15 × 40
X = 12
The distance, in feet, between the strip is therefore 12 feet
The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ==5
n=50
s orσ =5/=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?