65=8.06225774 this is the distance
Set it up as a direct variation: y/x=k, where k is the constant of variation. (20/3)/30=k gives us a k value of 8/9. The function would be y=8/9x
Answer:
The homeowner will require 9 strips of wallpaper.
Step-by-step explanation:
The question is asking <em>"how many 20 inches fit into 15 feet?".</em>
We know that
1 foot = 12 inches;
therefore, 15 feet will be
15 ft * 12 in/ft = 180 in.
Now, the number of 20 inches wallpaper strips that will fit into 180 in long wall will be
180 in/ 20 in = 9
Therefore, the homeowner will require 9 strips of wallpaper.
3x+2/5=7
3x+2/5=35/5
3x=35/5-2/5
3x=33/5
x=(33/5)/3
x=(33/5)/(3/1)
x=(33/5)*(1/3)
x=33/15
x=30/15+3/15=2+1/5
x=2.2
Answer: The company can build 10 child bikes and 12 adult bikes in the week .
Step-by-step explanation:
Let 'c' be the number of child bike and 'a' be the number of adult bike.
According to the problem
The restriction of building time for a week is 4c+6a≤120 hours.........(1)
and the restriction of testing time for a week is 4c+4a≤100 hours...............(2)
Lets check whether company can build c=10 and a=12 bikes in a week by putting this value in (1) and (2)
(1)......4(10)+6(12)=40+72=112≤120 ⇒Restriction of building time is satisfied.
(2)......4(10)+4(12)=40+48=88≤100⇒Restriction of testing time is satisfied.
Hence, the company can build 10 child bikes and 12 adult bikes in the week,as order is meeting with the restrictions.
