Answer:
74.30
Step-by-step explanation:
Let s = entry price for a student
Let t = entry price for a teacher
4s +5t = 95
6s+10t = 173
I will use elimination to solve this problem.
Multiply the first equation by -2
-2(4s +5t) = -2*95
Distribute
-8s - 10t = -190
Add this equation to the second equation to eliminate t
-8s - 10t = -190
6s+10t = 173
----------------------
-2s = -17
Divide by -2
-2s/-2 = -17/-2
s = 8.50
Now we need to find t
4s +5t = 95
Substitute s=8.50
4(8.50) +5(t) = 95
34 +5t = 95
Subtract 34 from each side
34-34 +5t = 95-34
5t = 61
Divide by 5
5t/5 = 61/5
t = 12.20
We want to find the cost for 3 students and 4 teachers
3s+4t
3(8.50) + 4(12.20)
25.50 + 48.80
74.30
Division and addition are the only operations involved.
If it’s just 40 in total for the whole session , $40 + (30 x (number of students) = ?
But if it’s 40 per student as well then (40 x 30) x (number of students) = ?
Please put the picture so I can answer the question
Answer:
b) 16 c) 0.95
Step-by-step explanation:
