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Lena [83]
2 years ago
9

Two joggers run 12 miles north and then 5 miles west. What is the shortest distance they must travel to return to their starting

point
Mathematics
1 answer:
Lera25 [3.4K]2 years ago
3 0

Answer:

13 miles

Step-by-step explanation:

It may be easier to use a diagram but I am going to try my best to explain without one.

Picture their journey north as one side of a right angle triangle (a). Now picture their journey west as another side (b).

The shortest journey back is the hypotenuse of the triangle (c).

Using pythagoras you can work out the answer

a^{2} + b^{2}  = c^{2}

5^{2} + 12^{2}  = c^{2}\\25 + 144 = c^{2} \\\\169 = c^{2}\\\sqrt{169}  = c^{2}  \\13 = c^{2}

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Round to the nearest tenth if necessary.
Andrei [34K]

Answer:

B) 25

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (-1, -8)

Point (-4, -4)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(-4--1)^2+(-4--8)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{(-3)^2+(4)^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{9+16}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{25}
  5. [√Radical] Evaluate:                                                                                           \displaystyle d = 5
4 0
2 years ago
.. Discuss the nature of the root of equation x2 + 2x + 3 = 0​
Mariana [72]

Answer:

  • No real roots

Step-by-step explanation:

Given equation:

  • x² + 2x + 3 = 0

On comparing the equation by ax² + bx + x = 0, We get: a = 1, b = 2 and c = 3

To Find the nature of the roots of the equation firstly we need to find the discriminant of the equation. The expression b²- 4ac is called the discriminant.

~

  • Two Distinct real roots, if b² - 4ac > 0
  • Two equal real roots, if b² - 4ac = 0
  • No real roots, if b² - 4ac < 0

\\ \: \: \dashrightarrow \: \: \: \sf  {b}^{2} - 4ac = 0 \\ \\ \\\: \: \dashrightarrow \: \: \: \sf (2)² - 4 \times 1 \times 3 = 0 \\  \\  \\ \: \: \dashrightarrow \: \: \: \sf 4 - 4 \times 1 \times 3 = 0  \\  \\  \\ \: \: \dashrightarrow \: \: \: \sf 4 - 12 = 0 \\  \\  \\ \: \: \dashrightarrow \: \: \: \sf {\underline{\boxed{\sf{\purple{  -8 > 0}}}}} \\  \\

The discriminant is smaller than 0.

  • <u>Hence, Equation has no </u><u>real</u><u> roots (no solution)</u>
6 0
1 year ago
bakery made 20 pies, half were pumpkin, a fourth were cherry, the rest were apple. how many were apple
Anastasy [175]
5 of the pies were apple
8 0
2 years ago
Read 2 more answers
What is the equation of this graphed line?
Liula [17]

Answer:

2,1

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
M (18, 24) is the midpoint of segment JL with J (- 4, - 2). What are the coordinates for L?
faust18 [17]

Answer:

mid point (x,y) = M (18, 24)

let J (- 4, - 2) be ( x1, y1)

     L(a,b) be (x2,y2)

using midpoint formula

(x,y) = [(x1+x2)/2, (y1 + y2)/2]

or, (18, 24) = [(-4+a)/2, (-2+b)/2]

comparing corresponding element we get

18 = (-4+a)/2                 24 =(-2+b)/2

or 36 = -4+ a            or 48 = -2 +b

or a = 40                  or b= 50

L(40,50)

5 0
3 years ago
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