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2 years ago

solve this system of linear equations, separate the x- and y-values with a comma. -13x=-96-7y -3x=64+7y

Mathematics

1 answer:

GaryK [48]2 years ago

6 0

Answer:

(2,-10)

Step-by-step explanation:

I used a graphing tool to graph the system of equations. The the two lines intercept at the point (2,-10). So, (2,-10) is the solution.

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2/5 × 6/7= simplify form

kirill115 [55]

Answer:

2 x 6 = 12

5 x 7 = 35

12/35

Step-by-step explanation:

3 0

2 years ago

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Find the surface area. round to the nearest hundredth when necessary.

Dmitry_Shevchenko [17]

Answer:

The surface area of the cuboid is 648 m^2

Step-by-step explanation:

What we have here is cuboidal in outlook

By using the formula for the surface area of a cuboid, we can get the surface area of the shape

mathematically, we have the surface area of a cuboid as follows;

2(lb + lh + bh)

where l is the length, b is the breadth (width) and h is the height

We can have the length as 9 m, the width as 9 m and the height as 13.5 m

Substituting these values, we have the surface area of the cuboid as;

A = 2(9(9) + 9(13.5) + 9(13.5))

A = 2(81 + 243)

A= 2(324)

A = 648 m^2

8 0

2 years ago

A gym employee is paid monthly. After working for three months, he had earned $4,500. To

Leto [7]

Answer:

$9000

Step-by-step explanation:

A gym employee has earned in 3 months =$4500

Then his monthly salary =$4500/3 =$1500

After six months he will earn = 6 × his monthly salary

= 6×$1500=$9000

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2 years ago

Cameron wants to buy a new bike that costs $112. He is saving $8 per week. How many weeks will it be until Cameron has all the m

leva [86]

the answer is 14

Step-by-step explanation:

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2 years ago

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A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?

kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

$f(x)=\frac{1}{2^{2x}}$ (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

$\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]$ (2)

To solve this derivative you use the following derivative formula:

$\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}$

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

$\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)$

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

$-2(ln2)2^{-2x}=-1$

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

$-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235$

With this value you calculate f(a):

$f(a)=\frac{1}{2^{2(0.235)}}=0.721$

Next, you use the general equation of line:

$y-y_o=m(x-x_o)$

for xo = a = 0.235 and yo = f(a) = 0.721:

$y-0.721=(-1)(x-0.235)\\\\y=-x+0.956$

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

$0=-x+0.956\\\\x=0.956$

hence, the x-intercept of the tangent line is 0.956

5 0

2 years ago