Answer:
Step-by-step explanation:
this idea is probably a good thing to have a solid understand of. That Cartesian (rect) is the x and y components, of the legs of a triangle and is a way to measure that part of the two leg of the triangle that is made up by those pieces.. while the polar system would measure the hypotenuse of that same triangle with the degrees as a way to place where that hypotenuses goes
the abs value of an imaginary number will give you that distance from the origin to the point.. if you are using that sqrt ( 
+ 
) to get the abs. this is the same as the magnitude and can represent a total force. The distance between the origin and the point is that idea of two points.. conveniently we used (0,0) the origin as one of the points.. the other is at the top of the line or the point given by the complex number
Hopefully that helps... :/
Let the length be l
Then,
l *(l-3)= 88
l²-3l =88
l²-3l-88=0
l²-11l +8l -88 =0
l(l-11) + 8(l-11) =0
(l+8)(l-11)=0
As, l can't be negative, length=11cm and width=(l-3)=11-3 =8 cm
6 meters, both mm and cm are too small to be reasonable, as lakes are deep enough to have boats on and to swim in.
Answer:
$10.348
Step-by-step explanation:
(3.98)(2.6)= 10.348
Let's define the vectors:
U = (4.4)
V = (3.1)
The projection of U into V is proportional to V
The way to calculate it is the following:
Proy v U = [(U.V) / | V | ^ 2] V
Where U.V is the point product of the vectors, | V | ^ 2 is the magnitude of the vector V squared and all that operation by V which is the vector.
We have then:
U.V Product:
U.V = (4,4) * (3,1)
U.V = 4 * 3 + 4 * 1
U.V = 12 + 4
U.V = 16
Magnitude of vector V:
lVl = root ((3) ^ 2 + (1) ^ 2)
lVl = root (9 + 1)
lVl = root (10)
Substituting in the formula we have:
Proy v U = [(16) / (root (10)) ^ 2] (3, 1)
Proy v U = [16/10] (3, 1)
Proy v U = [1.6] (3, 1)
Proy v U = [1.6] (3, 1)
Proy v U = (4.8, 1.6)
Answer:
the projection of (4,4) onto (3,1) is:
Proy v U = (4.8, 1.6)
