Answer:
hole at x=-3
Step-by-step explanation:
The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)
The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.
So anyways we have (x+3)/(x^2-9)
= (x+3)/((x-3)(x+3))
Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.
Answer:
-1
Step-by-step explanation:
You can write it as...
Carry the 4x
Then use the quadratic formula to solve, since you want to find the negative solution, you don't need to find the positive solution, so we will have
Therefore our answer is -1
Answer:
A = 177.46
Step-by-step explanation:
A = 6*6+6root((6/2)^2+11.4^2)+6root((6/2)^2+11.4^2)
A = 177.46
Answer:
a.) one sample t test
b.) H0 : μ = 59.3
c.) H1 : μ > 59.3
d.) μ = 59.3 ; σ = 39.84
e.) xbar = 79.4 ; s = 61.36
Test statistic = 3.16
Step-by-step explanation:
Given the sample data:
49.00 49.00 49.00 49.00 49.00 63.00 63.00 63.00 63.00 63.00 199.00 199.00 199.00 199.00 199.00 38.00 38.00 38.00 38.00 38.00 48.00 48.00 48.00 48.00 48.00 49.00 63.00 199.00 38.00 48.00
Sample size, n = 30
Using calculator :
xbar from the data above = 79.4
Standard deviation = 61.359
H0 : μ = 59.3
H1 : μ > 59.3
Test statistic :
(Xbar - μ) ÷ (σ/sqrt(n)
σ = 34.83
(79.4 - 59.3) ÷ (34.83/sqrt(30))
20.1 ÷ 6.359
Test statistic = 3.16
