Answer:
0.09269 M is the solubility at 25°C and 2070 Torr.
Explanation:
Solubility of carbon dioxide in water at 25°C and 795 Torr = 0.0356 M
That is 0.0356 mol of carbon dioxide in 1 L of water.
Mass of 0.0356 moles of carbon dioxide = 0.0356mol × 44 g/mol =1.5664 g
Solubility of carbon dioxide in water at 25°C and 2070 Torr =?
According to Henry's law that is mass of gas dissolved in liquid at constant temperatures is directly proportional to the pressure of the gas at equilibrium with the liquid.





Moles of carbon dioxide in 4.0785 g:
0.09269 mol in 1 L of water.
So, the concentration of carbon dioxide will be 0.09269 M.
0.09269 M is the solubility at 25°C and 2070 Torr.