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vovikov84 [41]
3 years ago
10

5.6

Chemistry
2 answers:
lesantik [10]3 years ago
7 0
200/19.32=10.352ms^-1
shutvik [7]3 years ago
6 0

Answer:

200/19.32=10.352ms^-1

Explanation:

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Which element in the third period would you expect to have the larger atomic radius, sodium (Na) or Sulfur (S)?
jeyben [28]

<u>Answer: </u>The correct answer is Option B.

<u>Explanation:</u>

The given elements that is sodium and sulfur are the elements which belong to the same period that is third period.

As, the electrons are added up to the same shell across a period, the number of protons also increase and hence, they attract the electrons more effectively. This means that the effective nuclear charge also increases and the size of the sulfur thus shrink and hence, the size (atomic radius) of sodium is the largest amongst third period.

Therefore, the correct answer is Option B.

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3 years ago
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Look this is a weird question to ask but am asking it anyways
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3 years ago
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Kp for the following reaction is 0.16 at 25 degree C. 2 NOBr(g) 2 NO(g) Br_2(g) The enthalpy change for the reaction at standard
finlep [7]

Answer:

Explanation:

Given that:

2 NOBr_{(g)} \iff 2 NO_{(g)} + Br_{2(g)}

From above:

K_p = 0.16 = \dfrac{(P_{NO})^2 (P_{Br})}{(P_{NOBr})^2}

To predict the effect of the addition of Br₂(g);

The addition of Br₂(g) will favor the equilibrium to shift to the left i.e. formation of NOBr

The removal of some NOBr will cause the equilibrium position to shift to the left side. This is because concentration on the left side is decreased and the concentration on the right side will be increased. Thus, the equilibrium will shift towards where the concentration is reduced which is the left side.

5 0
3 years ago
Caleb has a 860-kilogram car sitting in his back yard, gathering rust.
emmasim [6.3K]
<h3>Answer:</h3>

A. 860 kg

<h3>Explanation:</h3>

To answer the question we need to understand that;

  • Mass refers to the amount of matter in an object.
  • Weight, on the other hand, refers to the gravitational pull of an object to a given surface.
  • Mass is measured using a spring balance.

We also need to know that;

  • The mass of an object remains constant every where irrespective of the gravitational acceleration.
  • Therefore, an object on the surface of the earth would have the same mass as on the surface of the moon.
  • In this case; the mass of the car remains the same on the outer space as on the back yard.
3 0
3 years ago
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A substance has a volume of 10.0 cm3 and a mass of 89 grams. What is its density?
Irina18 [472]
Remembering that
d = m ÷ v

d = ?
m = 89 g
v = 10 cm³

Therefore:

d = 89 ÷ 10

d = 8,9 g÷cm³
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4 years ago
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