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Gnesinka [82]
3 years ago
6

I need lots of help and I really need it

Mathematics
1 answer:
Stells [14]3 years ago
8 0
Hi there! I can help you! So, 7/24 is less than 1/2 a day, because 1/2 is equivalent to 12/24 and 7/24 is less than 12/24. To find out how much less it is, let’s do subtraction.
12/24 - 7/24 = 5/24. 7/24 is less than half a day by 5/24.
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How would you teach something you have learned this year in Math to someone younger than you? Write more than 5 sentences.​
deff fn [24]

I would start by saying how much I enjoyed this lesson and how it has helped me in many ways I would also like to state how it was difficult at first but once I started to understand it, it became really easy and would like to thanks the teacher for teaching it.

4 0
3 years ago
Interoperate your solution in the context of the problem.<br> f(10)=1.75r+9
iVinArrow [24]

Answer:

Simplifying

f(r) = 5 + 1.75r

Multiply f * r

fr = 5 + 1.75r

Solving

fr = 5 + 1.75r

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'r'.

f = 5r-1 + 1.75

Simplifying

f = 5r-1 + 1.75

Reorder the terms:

f = 1.75 + 5r-1

Step-by-step explanation:

tada i think

6 0
4 years ago
Read 2 more answers
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666

Second step. <u>Calculate the standard deviation</u>

\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}

\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}

\sigma=\sqrt{17.815}=4.22

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).  

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

\bar X \pm t\frac{\sigma}{\sqrt n}

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0
3 years ago
I need to find the value of X
nirvana33 [79]

Answer:

17.7

Step-by-step explanation:

This figure is a pentagon - a shape with 5 sides. In a pentagon, the figure's angles add to 540.

100 + 7x-4 + 3x + 23 + 9x - 6 + 90 = 540

190 +19x + 13 = 540

203 + 19x = 540

19x = 337

x = 17.7

3 0
3 years ago
Can anyone help me with the problem in the picture?
torisob [31]
X = 45.

Since opposite exterior angles are congruent, you can set the 2 values equal to each other. When you solve for x, you should get 45.
3 0
3 years ago
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