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Alex
3 years ago
10

An investor has an account with stock from two different companies. Last year, her

Mathematics
1 answer:
lara [203]3 years ago
6 0

Answer:

4.5%

Step-by-step explanation:

800(1-0.01)=\color{green}{792}

800(1−0.01)=792

6180(1-0.05)=\color{blue}{5871}

6180(1−0.05)=5871

Last Year This Year

Stock A 800 792

Stock B 6180 5871

Total 6980 6663

\text{Find overall decrease:}

Find overall decrease:

6980(1-r)=6663

6980(1−r)=6663

\frac{6980(1-r)}{6980}=\frac{6663}{6980}

6980

6980(1−r)

​

=

6980

6663

​

1-r=0.954585

1−r=0.954585

-r=-0.045415

−r=−0.045415

Subtract 1

r=0.045415

r=0.045415

Divide by -1

\text{Final Answer: }4.5\%

Final Answer: 4.5%

Multiply by 100 and round to nearest 10th

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\displaystyle\sum_{r=1}^nr(r+1)\cdots(r+p-1)

When n=1,

\displaystyle\sum_{r=1}^1r(r+1)\cdots(r+p-1)=1(1+1)(1+2)\cdots(1+p-2)(1+p-1)=p!

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Assume it holds for n=k, i.e. that

\displaystyle\sum_{r=1}^kr(r+1)\cdots(r+p-1)=\frac{k(k+1)(k+2)\cdots(k+p-1)(k+p)}{p+1}

Now for n=k+1, you have

\displaystyle\sum_{r=1}^{k+1}r(r+1)\cdots(r+p-1)=\sum_{r=1}^kr(r+1)\cdots(r+p-1)+(k+1)(k+2)\cdots(k+1+p-1)
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as required.
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