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sammy [17]
3 years ago
9

I need heelllppppp plzzzz someone helllppp meee

Mathematics
1 answer:
horsena [70]3 years ago
8 0

Answer:

The equation of the line is y =  -\frac{4}{5} x + \frac{3}{5}

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

  • m is the slope
  • b is the y-intercept

The rule of the slope is m = \frac{y2-y1}{x2-x1} , where

  • (x1, y1) and (x2, y2) are two points on the line

∵ A line passes through points (2, -1) and (-3, 3)

∴ x1 = 2 ad y1 = -1

∴ x2 = -3 and y2 = 3

→ Use the rule of the slope above to find the slope of the line

∵ m = \frac{3--1}{-3-2} = \frac{3+1}{-5} = \frac{4}{-5}

∴ m = -\frac{4}{5}

→ Substitute the value of m in the form of the equation above

∴ y =  -\frac{4}{5} x + b

→ To find b substitute x and y in the equation by the coordinates of one  

   point of the given points

∵ x = 2 and y = -1

∴ -1 = -\frac{4}{5} (2) + b

∴ -1 = -\frac{8}{5} + b

→ Add \frac{8}{5} t both sides

∵ -1 + \frac{8}{5} = b

∴ \frac{3}{5} = b

→ Substitute the value of b in the equation

∴ y = -\frac{4}{5} x + \frac{3}{5}

∴ The equation of the line is y =  -\frac{4}{5} x + \frac{3}{5}

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1) El ritmo cardíaco de un gato ( en latidos por minuto) es función lineal de su temperatura corporal (en grados Celsius). En co
olga55 [171]

Answer:

y=10x-170

Step-by-step explanation:

This problem can be modeled by a linear function, where we have two points (37°C, 200) and (32°C, 150).

Notice that the temperature is the independent variable, because the heartbeat of the cat won't change the temperature, it works in the opposite way.

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This means the hearbeat of the car changes 10 pulses per minute each 1 celsius degree.

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