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Sergeeva-Olga [200]

3 years ago

8

Robert gets a loan from his bank.

1 answer:

GuDViN [60]3 years ago

8 0

He will of paid £420 as intrest

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What is the intersection of y=7 and y=1\2x+6

kotegsom [21]

Y=7 is just a straight horizonal line that is perpendicular to the y axis at 7

and y=1/2x+6, is in y=mx+b form where m=slope and b=yintercept so

to find the intersection, yo just find when both sentances are correct so

y=7
subsitute that into y=1/2x+6

7=1/2x+6
subtract 6 from both sides
1=1/2x
multiply both sides by 2
2=x

so the point (2,7) is the intersection

8 0

3 years ago

What is the solution to the equation sqrt5X-7= sqrt3X+5?<br> x = 1<br> x = 6<br> x = 12<br> x = 24

IgorC [24]

Answer:

X=6

Steps are in the picture

4 0

3 years ago

What is 0 = 8z + 8?

JulsSmile [24]

z equals -1 because 8 time negative one equals negative 8 plus 8 equals 0

3 0

3 years ago

Read 2 more answers

Which rule represents the translation of hexagon D'E'F'G'H'I' ?

Sveta_85 [38]

Answer:

C (X,Y)->(X-4,×-5) I would say bro

3 0

3 years ago

Would you need to use the chain rule to find the derivative of this function?

Nutka1998 [239]

Answer:

TRUE. We need to use the chain rule to find the derivative of the given function.

Step-by-step explanation:

Chain rule to find the derivative,

We have to find the derivative of F(x)

If F(x) = f[g(x)]

Then F'(x) = f'[g(x)].g'(x)

Given function is,

y = $\sqrt{2x+3}$

Here g(x) = (2x + 3)

and f[g(x)] = $\sqrt{2x+3}$

$\frac{dy}{dx}=\frac{d}{dx}(\sqrt{2x+3}).\frac{d}{dx} (2x+3)$

y' = $\frac{1}{2}(2x+3)^{(1-\frac{1}{2})}.(2)$

= $(2x+3)^{-\frac{1}{2}}$

y' = $\frac{1}{\sqrt{2x+3}}$

Therefore, it's true that we need to use the chain rule to find the derivative of the given function.

8 0

3 years ago