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3 years ago

Plz help me thank you 15 points plz help me fast thank you so much plz only if you can understand I really need help

Mathematics

2 answers:

Kipish [7]3 years ago

8 0

Answer:

Meters

Step-by-step explanation:

As we can see that iceberg Is not so small so using the inches and millimeters for measuring its height would be a very Unit and we will need a lot of inches to do so

In case of square centimeters and square kilometers we can not use these kind of units to measure the height of an iceberg because of the reason that these are the units of the area and height is in this case is the distance between bottom to top so for measuring distance we can not use the units of area

In case of kilo meter it is a large unit to measure the height of the ice berg. It could be used to measure height but in this case we will get the answer in very small values so scaling it would not be easy

So the last option left with us is meters which would be used to measure the Height of the ice berg it is also the SI unit of length so it is also the best unit because it is either not so small or not so large so that why it could be used.

Also meters is used by the scientists too so it is a standard unit and all other units are created from it. This gives all scientists the same standards of measurement during an experiment.

KATRIN_1 [288]3 years ago

7 0

Answer:

inches is better

Step-by-step explanation:

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Brandon made $38.00 in 3 hours. How much would he make in 10 hours

Bad White [126]

Answer:

He would make $126.70 in 10 hours.

Step-by-step explanation:

First, you have to find the unit rate, in other words, how much money he earns in one hour. To do that, you have to divide.

38.00÷3= 12.666667

Once you know how much money Brandon earns in one hour($12.67), you multiply that number by 10.

12.67×10= 126.70

In conclusion, the answer to this solution($126.70) is how much money he earns in 10 hours.

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3 years ago

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What is the value of F in the formula F=9/5C+32 when C=30?

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kiruha [24]

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For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

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3 years ago

Hey:) can you please help me posted picture of question

juin [17]

Answer:
x² - 10x + 21

Explanation:
To answer this question, we will simply multiply each term from the first bracket by each term from the second and then combine like terms to get the final expression.

This can be done as follows:
(x - 3)(x - 7)
x(x) + x(-7) -3(x) -3(-7)
x² - 7x - 3x + 21
x² - 10x + 21

Hope this helps :)

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