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jeka94
3 years ago
14

The figure is made up of a square and a rectangle. Find the area of the shaded region.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

9

Step-by-step explanation:

second box is nine because it is half of the 3 x 6 part

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What is 3/4 plus 4 1/3
OlgaM077 [116]

Answer:

Step-by-step explanation:

You need to change the denominator into a the least common denominator, 4 and 3 both have 12 in common. 12 is your new denominator but what you to the bottom you must do to the top. So when you multiply 3/4 by 3/3 you will get 9/12.

Then you want to make 4 1/3 into a improper fraction, which would be 13/3 you want to multiply this by 4 and you will get 52/12. You will then add 52/12 to 9/12 and get 61/12 or 5 1/12.

If you need any more help please let me know.

4 0
3 years ago
How to solve this I am not the best at math
Brrunno [24]
Try  it is a great site that you can plug problems in to for the answers! I hope this is helpful!!
5 0
4 years ago
If a square block is 17 centimeters on one side.what is the perimeter of the block?
emmasim [6.3K]
If a shape is a square, this mean that each side has the same length. This means that each side of the square has a length of 17cm. Perimeter is the length of the outer boundary of a shape or the summation (addition) of all the sides. This means that the perimeter of this square is 17+17+17+17 or 17×4 which is equal to 68cm.
I hope this helps!
6 0
4 years ago
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What would happen to the perimeter of a shape when the dimensions are multiplied by 10
Mrrafil [7]

Answer:

Be 10 times larger.

Step-by-step explanation:

Imagine the perimeter is just 10. If it got 10 times larger, it goes to 100.

6 0
3 years ago
3 sisters are each 2 years apart in age. The youngest sister is Emily the middle sister Samantha and the older sister is Lauren
Jet001 [13]
Emily is 12, Samantha is 14, and Lauren is 16. Basically all you do to solve this problem is add numbers that are two apart until you find something. 

Ex. 2+4+6=12  4+6+8=18 so on and so forth. 
3 0
3 years ago
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