Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Answer:
Step-by-step explanation:
46+x=77 subtract 46 from both sides
x=31
Answer:
75.3 kg
Step-by-step explanation:
mark as BRAINLIST answer
Answer:
-0.65, -0.35, 4, 5
Step-by-step explanation:
The bigger the number is in negatives the farther the way it is away from 0, therefore making -0.65 the least number.
Answer:
n=9/8
Step-by-step explanation:
divide both sides by 8
