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Maslowich
3 years ago
6

Is the system of equations is consistent, consistent and coincident, or inconsistent?

Mathematics
2 answers:
vampirchik [111]3 years ago
8 0

Answer: I also took the test and the answer is consistent and coincident. It was right.

kicyunya [14]3 years ago
5 0
<span><span>Hiya!

Y=−3x+1
</span><span>
2y=−6x+2

The answer is...

</span></span><span>consistent and coincident
</span>
Hope This Helps!
(If it Helps I took the test, its 100% Right)
(Brainliest is always appreciated)
If You Have Any More Questions Feel Free To Ask! :)
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Find the 11th term of the geometric sequence 6, -18, 54<br> AYUDEN CHUCHA
otez555 [7]

Step-by-step explanation:

T1=a

T2=ar

r=T2÷T1

r=--18÷6

r=-3

T11=ar^10

T11=6×-3^10

T11=-354294

8 0
4 years ago
Read 2 more answers
Make x the subject y=3x-2
Sedaia [141]
First, let's add the two from both sides.
y + 2 = 3x - 2 + 2
y + 2 = 3x

Now, all we have to do is to divide both sides by 3.
(y + 2)/3 = (3x)/3
(y + 2)/3 = x

And now, flip both sides around so it looks nicer.
x = (y + 2)/3
5 0
3 years ago
There are 2 green marbles, 4 blue marbles, 1 red marble, and 8 yellow marbles in a bag. Once a marble is drawn, it is NOT replac
Cloud [144]

Answer:

1/15

Step-by-step explanation:

You have to count all of the numbers for a total AKA the denominator. Since you're only picking one marble, the numerator is 1.

5 0
4 years ago
Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appea
makkiz [27]

Answer:

0.2

Step-by-step explanation:

If two number cubes as tossed then the total possible out comes are

Total = {(1,1),(2,1),(3,1),(4,1),(5,1),(6,1),(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,5),(2,5),(3,5),(4,5),(5,5),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}

Number of elements in sample space are

n(S)=36

Let A and B represent the following events.

A = The sum will be 4.

A = {(1,3),(2,2),(3,1)}

n(A) = 3

B = The sum is less than or equal to 6.

B = {(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}

n(B)=15

Intersection of both events is

A∩B = {(1,3),(2,2),(3,1)}

n(A∩B) = 3

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{3}{36}

P(B)=\dfrac{n(B)}{n(S)}=\dfrac{15}{36}

P(A\cap B)=\dfrac{n(A\cap B)}{n(S)}=\dfrac{3}{36}

We need to find the probability that the sum will be 4, given that the sum is less than or equal to 6.

P(\frac{A}{B})=\dfrac{P(A\cap B)}{P(B)}

P(\frac{A}{B})=\dfrac{\frac{3}{36}}{\frac{15}{36}}

P(\frac{A}{B})=\dfrac{3}{15}

P(\frac{A}{B})=\dfrac{1}{5}

P(\frac{A}{B})=0.2

Therefore, the required probability is 0.2.

3 0
3 years ago
9,-81, 729,-6561...<br> What is the common ratio?<br> Help which is the correct answer?
GrogVix [38]

Answer:

r = -9

Step-by-step explanation:

Given

Sequence: 9,-81, 729,-6561...

Required

Determine the common ratio

The common ratio r is calculated using:

r = \frac{T_n}{T_{n-1}}

Let n = 2

So, we have:

r = \frac{T_2}{T_{2-1}}

r = \frac{T_2}{T_1}

From the sequence:

T_2 = -81

T_1=9

So, the equation becomes

r = \frac{-81}{9}

r = -9

7 0
3 years ago
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