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4 years ago

Solve this system of equations by graphing. First graph the equations, and then type the solution.

Mathematics

1 answer:

tiny-mole [99]4 years ago

7 0

Here the graph and what else you need

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(4 - 1+ 3/3) 15

ANEK [815]

Solve for what expresssion don’t

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3 years ago

Round 169,750 to the nearest hundred thousand

Allushta [10]

Answer:

200,000

Step-by-step explanation:

5 0

3 years ago

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For number 6, evaluate the definite integral.

maks197457 [2]

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\$

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64$

$\bf \\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2} \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3$

3 0

3 years ago

Determine the temperature of 2.6 moles of gas contained in a 5.00-L vessel at a pressure of 1.2atm.

strojnjashka [21]

Answer:

28.108 K.

Step-by-step explanation:

Given: Pressure (P)= 1.2atm

Number of moles (n)= 2.6 moles

Volume (V)= 5.00-L

Now finding the temperature (T).

Formula; T= $\frac{P\times V}{n\times R}$

R is a constant factor which makes other factors work together.

There is a numerical value for R which we use is $0.0821 \times \frac{L.atm}{mole.K}$

∴ Temperature (T)= $\frac{1.2\times 5}{2.6\times 0.0821 \frac{L.atm}{mol.K} }$

⇒ Temperature (T)= $\frac{6}{0.21346} = 28.1083\ K$

∴ Temperature is 28.108 K

8 0

3 years ago

What is the square route of five

CaHeK987 [17]

<u><em>Answer: =2.23</em></u>

Step-by-step explanation:

Square root like this: √

5=2.23

You can also round up to the nearest hundredths and it's going to be stay. If the digit is 5 or more it's going to round up to the nearest tenths, hundredths, and thousandths.

Hope this helps!

Thank you!

Have a great day!

6 0

3 years ago

Read 2 more answers