Answer:
The answer to your question is 37.5
Answer:
One-sixth times StartFraction 2 over 1 EndFraction
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5: Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
Answer:
The result is the same.
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
Given the information:
- square 12 inches wide
- 3-inch diameter cookies are cut => its radius is: 1.5 inches
Hence we can find some information:
- The area of the square is:
square inches - The area of a cookies is:
π = 3.14*
= 7.065 square inches - The total number of 3-inch cookies are: 4*4 =16
=> The total area of the cookies is: 16* 7.065 = 113.04 square inches
=> how much cookie dough is "wasted" when 3-inch cookies are cut:
= The area of the square - The total area of the cookies
= 144 - 113.04 = 30.96 square inches
If the diameter is increased to 4 inches => its radius: 2 inches, we have:
- The area of a cookies is:
π =
square inches - The total number of 3-inch cookies are: 3*3 =9
=> The total area of the cookies is: 9* 12.56 = 113.04 square inches
=> how much cookie dough is "wasted" when 4-inch cookies are cut:
= The area of the square - The total area of the cookies
= 144 - 113.04 = 30.96 square inches
The result is the same.