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Alex Ar [27]
3 years ago
5

PLEASE HELP! I WILL MAKE YOU BRAINLIST!

Mathematics
2 answers:
Luda [366]3 years ago
6 0

Answer:

The answer is A

Step-by-step explanation:

Blababa [14]3 years ago
5 0

The answer is A, because the perimeter in cm is 19 and if we multiply 19 by 6.5 we get 61.75

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PLEASE HELP FAST triangle abc is translated 4 units down and 6 units right, resulting in triangle A’B’C’
Lina20 [59]

Answer:

D. (6,-1)

Step-by-step explanation:

Translating is just sliding slide the point B down 4 units from where it is and then move over 6 units to the right.

6 0
3 years ago
Please help me!!! will mark brainlest
Licemer1 [7]

A. To be able to have the 2 sides ( the 2 triangles) line up correctly, Net A would be the correct one.


B. AB = 3

BC = 5

CD = 9.4



C. Surface area:

9.4 x 5 = 47

9.4 x 3 = 28.2

9.4 x 4 = 37.6

3 x 4 = 12


Total: 47 + 28.2 + 37.6 + 12 = 124.8 sq. in.

8 0
3 years ago
What is the area to this shape ?
Dafna1 [17]

Answer:

249.42 units²

Step-by-step explanation:

Given only the apothem of an n-sided regular polygon, the area can be computed as ...

... A = n·a²·tan(180°/n)

For n=3 and a=4√3, this is ...

... A = 3·(4√3)²·tan(60°)

... A = 3·48·√3 = 144√3 . . . . units²

... A ≈ 249.42 units²

4 0
3 years ago
Two friends leave school at the same time Sarah is heading to do North and Beth is heading to West one hour later they are 5 mil
svet-max [94.6K]
5^-4^=25-16=9 root from 9 is 3 so it’s c) 3 miles
7 0
3 years ago
The mean per capita income is 16,127 dollars per annum with a variance of 682,276. What is the probability that the sample mean
MakcuM [25]

Answer:

0.60% probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

The standard deviation is the square root of the variance. So

\mu = 16127, \sigma = \sqrt{682276} = 826, n = 476, s = \frac{826}{\sqrt{476}} = 37.86

What is the probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

Either it differs by 104 or less dollars, or it differs by more than 104 dollars. The sum of the probabilities of these events is 100. I am going to find the probability that it differs by 104 or less dollars first.

Probability that it differs by 104 or less dollars first.

pvalue of Z when X = 16127 + 104 = 16231 subtracted by the pvalue of Z when X = 16127 - 104 = 16023. So

X = 16231

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16231 - 16127}{37.86}

Z = 2.75

Z = 2.75 has a pvalue of 0.9970

X = 16023

Z = \frac{X - \mu}{s}

Z = \frac{16023 - 16127}{37.86}

Z = -2.75

Z = -2.75 has a pvalue of 0.0030

0.9970 - 0.0030 = 0.9940

99.40% probability that it differs by 104 or less.

What is the probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

p + 99.40 = 100

p = 0.60

0.60% probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

7 0
3 years ago
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