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Kay [80]
2 years ago
13

Mr. smith has 5 courses he teaches at the community college. his course a has 102 students with an average tardiness of 3 studen

ts each day. another course has an average tardiness of 5 students each day with 85 enrolled. the average of these two courses receive a b+. what percent of students are tardy in course a? do not include % in answer and round to nearest hundredth. example, if answer is 19.567%, put 19.57.
Mathematics
1 answer:
Furkat [3]2 years ago
5 0

The percentage of tardiness among the 102 pupils is 2.94.

<h2>Calculation of the percentage</h2>

According to the query,

Course A: Total number of students = 102

                   Number of tardy students = 3

Percent of students tardy in course A = (number of tardy students/total  

                                                                   number of students) * 100

  =(3/102)*100

  = 2.941

  ≈2.94

In case of course B: Total number of students = 85 & tardy student = 5

So, the percent of tardy student = (5/85)*100 = 5.88 %

Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.

Learn more about the percentage here:

brainly.com/question/92258

#SPJ4

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Hello!

After reading the question you have provided I have come up with the correct numerical expression:

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Step-by-step explanation:

To come up with this solution you need to keep in mind some of the terminoloy being used.

The word "subtract" comes from the action of subtraction

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Thus, using those terminologies correctly, you can then deduce that when the question says "the product of 4 and 5" means "multiplying 4 and 5 together".

So you get the first part being 4x5

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4x5-1

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Two angels re supplementary. The larger angle is 48 degrees more than the 10 times the smaller angle. Find the measure of each a
evablogger [386]
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STEP 1:
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Add the two angles above to equal 180.

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STEP 2:
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