All categories

3 years ago

Pls help! will give brainlist!

Mathematics

2 answers:

Vlad [161]3 years ago

6 0

(0,1) is the correct answer I had just answered a question

Agata [3.3K]3 years ago

5 0

(-1, 0)

As you can see, they're clearly intersecting at that point, which means that the solution is that point.

You might be interested in

3(2-0.9h)+(-1.3h-4) does anyone know the answer

natta225 [31]

Answer:

-1.3h - 0.7

Step-by-step explanation:

it is an expression not an answer

3 0

3 years ago

Read 2 more answers

Help please! Could you explain it too?

Olegator [25]

Answer:

a. Not proportional

b. Proportional;

k = ⅞

Step-by-step explanation:

A proportional relationship is usually represented in the format, y = kx. k here represents constant of proportionality. This shows that x and y are directly proportional.

a. y = -2x + 9 is not a proportional equation.

b. y = ⅞x is a proportional equation.

Constant of proportionality: k = ⅞

8 0

3 years ago

For trapezoid JKLM, A and B are midpoints of the legs. Find AB.

romanna [79]

Answer:

Step-by-step explanation:

The length of the median of a trapezoid equals one-half the sum of the lengths of the bases.

$\begin{array}{rcl}AB & = & \frac{1}{2}(JK + LM)\\\\& = & \frac{1}{2}(19 + 39)\\\\& = & \frac{1}{2}\times 58\\\\& = & \mathbf{29}\\\end{array}$

8 0

4 years ago

The function g is related to one of the parent functions g(x) = x2 – 3 The parent function is: f(x)= x^2 Use function notation t

krek1111 [17]

g(x) is a translation of f(x), we have:

g(x) = f(x) - 3

<h3>How to write g(x) in terms of f(x)?</h3>

We have the two functions:

$g(x) = x^2 - 3\\\\f(x) = x^2$

We can see that g(x) is just a translation of 3 units downwards of f(x), to write g(x) in terms of f(x) we can just replace the first term by f(x):

$g(x) = x^2 - 3 = f(x) - 3$

So we have:

g(x) = f(x) - 3

If you want to learn more about translations:

brainly.com/question/24850937

#SPJ1

6 0

2 years ago

Find K by evaluating Limit

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

$\lim_{x \to \infty}\frac{1-cos4x}{1-cos2x}= \lim_{x \to 0} \frac{(1-cos4x)'}{(1-cos2x)'}= \lim_{x \to 0}\frac{4sin4x}{2sin2x}= \lim_{x \to 0}\frac{2*2sin2xcos2x}{sin2x}\\ = \lim_{x \to 0}4cos2x\\ =4$

{L'Hospital's rule}

<em>I hope this helps you</em>

6 0

2 years ago