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3 years ago

Differentiate: y=152+26−37 dy/dx= answer

Mathematics

1 answer:

ozzi3 years ago

8 0

Answer:

$\frac{dy}{dx} y=0$

General Formulas and Concepts:

Calculus

The derivative of a constant is equal to 0

Step-by-step explanation:

Step 1: Define function

y = 152 + 26 - 37

Step 2: Simplify

Combine like terms

y = 141

Step 3: Find derivative

Derivative of any constant will be 0.

$\frac{dy}{dx} y=0$

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A car traveling 281 miles 4 hours and 40 minutes what was the average speed of the car in miles per hours

den301095 [7]

ok this one is tricky but I think I can handle it.

The correct answer is more than 60mph but less than 61mph.

60.3mph = 281.399598

or 60.2mph =280.932932

Those are my closest answers.

I really hope this helps

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4 years ago

F(n) = 2• (-3)^n

Mashutka [201]

Answer:

$f(1)=-6$

$f(n)=f(n-1)(-3)$

Step-by-step explanation:

We are given that

$f(n)=2\cdot (-3)^n$

We have to complete the recursive formula of f(n).

Substitute n=1

$f(1)=2\cdot (-3)$

$f(1)=-6$

$f(2)=2\cdot (-3)^2=18$

$f(3)=2\cdot (-3)^3=-54$

$\frac{f(2)}{f(1)}=\frac{18}{-6}=-3$

$\frac{f(3)}{f(2)}=\frac{-54}{18}=-3$

It forms geometric sequence because the ratio of two consecutive terms are equal.

Therefore, the recursive formula

$f(n)=f(n-1)r$

$f(n)=f(n-1)(-3)$

7 0

3 years ago

Read 2 more answers

Let z = ln(x 2 + y), x = ret . and y = ter . Use the Chain Rule to compute ∂z ∂r and ∂z ∂t at the point where (r, t) = (1, 2).\

Natali [406]

By the chain rule,

$\dfrac{\partial z}{\partial u}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial u}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial u}$

where $u\in\{r,t\}$ .

We have component partial derivatives

$\dfrac{\partial z}{\partial x}=\dfrac{2x}{x^2+y}=\dfrac{2re^t}{r^2e^{2t}+te^r}$

$\dfrac{\partial z}{\partial y}=\dfrac1{x^2+y}=\dfrac1{r^2e^{2t}+te^r}$

$\dfrac{\partial x}{\partial r}=e^t$

$\dfrac{\partial x}{\partial t}=re^t$

$\dfrac{\partial y}{\partial r}=te^r$

$\dfrac{\partial y}{\partial t}=e^r$

Putting the appropriate pieces together and setting $(r,t)=(1,2)$ , we get

$\dfrac{\partial z}{\partial r}(1,2)=\dfrac{2e^3+2}{e^3+2}$

$\dfrac{\partial z}{\partial t}(1,2)=\dfrac{2e^3+1}{e^3+2}$

3 0

3 years ago

The length of the hypotenuse line segment AC in right triangle ABC is 25 cm. The length of line segment BC is 15 centimeters. Wh

Elden [556K]

From my understanding you ahould use the trig function cos to solve this.
cos(c) = 15/25 or 0.6
if you have this following function on your calculator I suggest using it:

cos ^{ - 1}

by using the function like so:

cos^{ - 1} (0.6

you should get about 53.13° (rounding to the nearest hundredth)
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8 0

3 years ago

Read 2 more answers

30 POINTS!!!!!!

scoundrel [369]

Answer:

I think the answer is C

Step-by-step explanation:

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3 years ago