We know that
1) empirical formula of a compound is the representation of a molecules with the elements in simplest mole ratio.
2) the molar mass is the actual proportion of moles of elements present in a molecule
3) there is a simple ratio between the molar mass and empirical mass a molecule
Now let us solve each problem
1) empirical formula of
will be 
2) empirical formula of
will be 
3) empirical formula of
will be 
4) the molecular formula will be :

the molecular formula = 4 X empirical formula = 4 X CO = 
5) the mole ratio of Cl and Cr is 
empirical formula will be 
Linear molecule with two domains
Explanation:
The describe geometry of the substance fits that of a linear molecule with two domains.
This description is based on the VSEPR i.e Valence Shell Electron Pair repulsion(VSEPR) model. It states that if an atom is bonded by two or more kinds of atoms the shape is determined by the geometry of the bonds around the central atom.
The electron domain is the number of lone pairs of electron around an atom.
Here in CO₂:
there are two lone pairs and the oxygen atoms are in a 180° linear shape around the central carbon atom. The bond is made up of two O⇔C structure.
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Answer:
It matters
Explanation:
Pure substance are known to have a sharp freezing point. However, the presence of solute lowers the freezing point of the solvent. The best time to measure the freezing point is when the freezing process is just beginning.
It will be an error to measure the freezing point when the part of the solution has already frozen.
The labels the table to indicate when each statement Is true. Labels can be used once, more than once, or not at all, The orange dye moves independently of the purple dye. 2. Concentration gradients exist that drive diffusion of both dyes. : <u>free water, solute, free water, solute.</u>
In chemistry, attention is the abundance of a constituent divided by way of the total quantity of an aggregate. several types of mathematical descriptions may be prominent: mass concentration, molar concentration, range concentration, and quantity concentration.
it's miles the amount of solute dissolves in one hundred g solvent. If the attention of the answer is 20 %, we understand that there are 20 g solutes in one hundred g solution. instance: 10 g salt and 70 g water are mixed and the solution is ready. find awareness of the answer by means of percentage mass.
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